Prove that: ^242^ - ^278^ = 15+1 8 - Vidyadip

Question

Prove that: $\sin^242^\circ-\cos^278^\circ=\frac{\sqrt{15}+1}{8}$

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Answer

$\text{LHS}=\sin^242^\circ-\cos^278^\circ$ $=\sin^2(90-48)-\cos^2(90-12)$ $=\cos^248^\circ-\sin^212^\circ$ $=\cos(48+12).\cos(48-12)$$\big[\because\cos(\text{A+B}).\cos(\text{A}-\text{B}=\cos^2\text{A}-\sin^2\text{B})\big]$ $=\cos60^\circ.\cos36^\circ$ $=\frac{1}{2}.\frac{\sqrt{5}+1}{4}$ $\Big[\because\cos36^\circ=\frac{\sqrt{5}+1}{4}\Big]$ $=\frac{\sqrt{5}+1}{8}$ $=\text{RHS}$

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