Question
Prove that $\sqrt{5}$ is an irrational number.

Answer


Let $\sqrt{5}$ be a rational number.
$\therefore \sqrt{5}=\frac{p}{q}$, where $q \neq 0$ and let $p \& q$ be co-prime.
$5 q ^2= p ^2 \Rightarrow p ^2$ is divisible by $5 \Rightarrow p$ is divisible by $5.....$  (i)
$\Rightarrow p =5 a$, where ' a ' is some integer
$25 a^2=5 q^2 \Rightarrow q^2=5 a^2 \Rightarrow q^2$ is divisible by $5 \Rightarrow q$ is divisible by 5 ........ (ii)
(i) and (ii) leads to contradiction as ' $p$ ' and ' $q$ ' are co-prime.
$\therefore \sqrt{5}$ is an irrational number.

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