Question
Prove that $(\text{cosec A}-\cot\text{A})^2=\frac{(1-\cos\text{A})}{(1+\cos\text{A})}.$

Answer

$(\text{cosec }\text{A}-\cot\text{A})^2=\frac{(1-\cos\text{A})}{(1+\cos\text{A})}$$\text{LHS}=(\text{cosec }\text{A}-\cot\text{A})^2$
$=\Big(\frac{1}{\sin\text{A}}-\frac{\cos\text{A}}{\sin\text{A}}\Big)^2$
$=\Big(\frac{1-\cos\text{A}}{\sin\text{A}}\Big)^2$
$=\frac{(1-\cos\text{A})^2}{\sin^2\text{A}}$
$=\frac{(1-\cos\text{A})^2}{1-\cos^2\text{A}} $ $\Big[\because\sin^2\theta+\cos^2\theta=1\Big]$
$=\frac{(1-\cos\text{A})(1-\cos\text{A})}{(1-\cos\text{A})(1+\cos\text{A})}$
$=\frac{(1-\cos\text{A})}{(1+\cos\text{A})}=\text{RHS}$
Hence proved.

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