Equation of travelling wave
\(y=a \sin 2 \pi\left(p t-\frac{x}{5}\right)\)
Maximum particle velocity \(\left(v_y\right)=A \omega\) or \(v_y=a \times 2 \pi p\)
Wave velocity \((v)=\frac{\omega}{k}=\frac{2 \pi p}{2 \pi / 5}=5 p\)
\(\therefore \frac{v_y}{v}=\frac{2 \pi a}{5}\)
(હવામાં ધ્વનિની ઝડપ $=330\, ms^{-1}$)