\(a=100,\) \(a-x=0.1\)
\({{t}_{1}}=\frac{2.303}{K}\log \frac{100}{0.1}\)
\(=\frac{2.303}{K}\log {{10}^{3}}\),
\({{t}_{2}}=\frac{2.303}{K}\log \frac{100}{50}\)
\(=\frac{2.303}{K}\log \,2\)
\(\frac{{{t_1}}}{{{t_2}}}\, = \,\frac{3}{{0.3010}}\, = \,10\)
$\mathrm{N}_{2}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{g})$
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