માટે સંતુલન પુરોગામી દિશામાં .......... દ્વારા ખસે.
equilibrium. This change in the direction of equilibrium is governed by Le-Chatelier's principle. According to Le-Chatellier's principle, equilibrium shifts in die opposite direction to undo the change. $\mathrm{N}_{2}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{g})+\mathrm{Heat}$
(a) Increasing the concentration of $N H_{3}(g):$ On increasing the concentration of $N H_{3}(g)$. the equilibrium shifts in the backward direction where concentration of $N H_{3}(g)$ decreases
(b) Decreasing the pressure: since, $p \propto n$ (number of moles), therefore, equilibrium shifts in the backward direction where number of moles are increasing.
(c) Decreasing the concentration of $N_{2}(g)$ and $H_{2}(g)$ Equilibrium shifts in the backward direction when concentration of $H_{2}(g)$ and $H_{2}(g)$ decreases.
(d) Increasing pressure and decreasing temperature: On increasing pressure, equilibrium shifts in the forward direction where number of moles decreases. It is an example of exothermic reaction therefore decreasing temperature favours the forward direction
$Co{O_{2\left( g \right)}} + C{O_{\left( g \right)}} \rightleftharpoons Co{O_{\left( s \right)}} + C{O_{2\left( g \right)}}\,\,;\,K = 490$
તો નીચેની પ્રક્રિયા માટે સંતુલન અચળાંક .... થશે.
$C{O_{2\left( g \right)}} + {H_{2\left( g \right)}} \rightleftharpoons C{O_{\left( g \right)}} + {H_2}{O_{\left( g \right)}}$
$298 \,K$ પર, ઉપરની પ્રક્રિયા માટે $K _{ c }$ એ $3.0 \times 10^{-59}$ મળેલ છે. જો $O _{2}$ની સંતુલન સાંદ્રતા $0.040\, M$ હોય તો પછી $O _{3}$ ની સાંદ્રતા $M$ માં શોઘો.