Question
✓
Answer
(i) 1 and 4
(ii) 𝑥 = $5 / 2$
(iii) (A) At $x=5 / 2, p(x)=2.25$
Therefore, $h=0.10+2.25=2.35 m$
OR
(B) $-x^2+5 x-4=2$
$x^2-5 x+6=0$
$(x-2)(x-3)=0$
$\Rightarrow x=2$ and $x=3$
Therefore, required points are (2,0) and (3,0)
(ii) 𝑥 = $5 / 2$
(iii) (A) At $x=5 / 2, p(x)=2.25$
Therefore, $h=0.10+2.25=2.35 m$
OR
(B) $-x^2+5 x-4=2$
$x^2-5 x+6=0$
$(x-2)(x-3)=0$
$\Rightarrow x=2$ and $x=3$
Therefore, required points are (2,0) and (3,0)
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