Question
Rationalize the denominators of $\frac{1}{{\sqrt 7 - 2}}$

Answer

$\eqalign{ & {1 \over {\sqrt 7 - 2}} \cr & = {1 \over {\sqrt 7 - 2}} \times {{\sqrt 7 + 2} \over {\sqrt 7 + 2}} \cr & = {{\sqrt 7 + 2} \over {{{(\sqrt 7 )}^2} - {{(2)}^2}}} = {{\sqrt 7 + 2} \over {7 - 4}} \cr & = {{\sqrt 7 + 2} \over 3} \cr}$

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