MCQ
Reaction of $B{r_2}$ on ethylene in presence of $NaCl$ gives
  • A
    $BrC{H_2} - C{H_2}Br$
  • B
    $ClC{H_2} - C{H_2}Br$
  • Both $(a)$ and $(b)$
  • D
    None of these

Answer

Correct option: C.
Both $(a)$ and $(b)$
c
(c) $C{H_2} = C{H_2}\, + B{r_2}   \xrightarrow{NaCl} \mathop {\mathop {C{H_2}}\limits_{\mathop {|\,\,\,\,\,\,\,}\limits_{Br\,\,\,} }  - \mathop {C{H_2}}\limits_{\mathop {|\,\,\,\,\,\,\,\,}\limits_{Br\,\,\,} } }\limits_{{\rm{1,2}} - {\rm{dibromo}}\,{\rm{ethane}}} $    $\mathop { + \mathop {C{H_2}}\limits_{\mathop {\,\,|\,\,\,\,\,\,\,\,\,}\limits_{Cl\,\,\,} }^{2\,\,\,\,\,\,}  - \mathop {C{H_2}}\limits_{\mathop {|\,\,\,\,\,\,}\limits_{Br\,\,} }^{1\,\,\,\,\,\,\,} }\limits_{{\rm{1}} - {\rm{bromo}} - {\rm{2}} - {\rm{chloro}}\,{\rm{ethane}}} $

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