Question
Read the passage given below and answer the following questions from 1 to 5.
The dipositive oxidation state $(M^{2+})$ is the Predominant valence of Group 2 elements. The Alkaline earth metals form compounds which Are predominantly ionic but less ionic than the Corresponding compounds of alkali metals. This is due to increased nuclear charge and Smaller size. The oxides and other compounds Of beryllium and magnesium are more covalent Than those formed by the heavier and large Sized members (Ca, Sr, Ba). The general Characteristics of some of the compounds of Alkali earth metals are described below.
Oxides and Hydroxides: The alkaline Earth metals burn in oxygen to form the Monoxide, MO which, except for BeO, have Rock-salt structure. The BeO is essentially Covalent in nature. The enthalpies of formation Of these oxides are quite high and consequently They are very stable to heat. BeO is amphoteric While oxides of other elements are ionic in Nature. All these oxides except BeO are basic In nature and react with water to form sparingly Soluble hydroxides.
$MO + H2O \rightarrow M(OH)_2$
The solubility, thermal stability and the Basic character of these hydroxides increase With increasing atomic number from $Mg(OH)_2 To Ba(OH)_2$.The alkaline earth metal Hydroxides are, however, less basic and less Stable than alkali metal hydroxides. Beryllium Hydroxide is amphoteric in nature as it reacts With acid and alkali both.
$Be(OH)_2 + 2OH^– \rightarrow [Be(OH)4]^{2–}$
Beryllate ion
$Be(OH)_2 + 2HCl + 2H_2O \rightarrow [Be(OH)_4]Cl_2$​​​​​​​
Halides: Except for beryllium halides, all Other halides of alkaline earth metals are ionic In nature. Beryllium halides are essentially Covalent and soluble in organic solvents. Beryllium chloride has a chain structure in the Solid state as shown below: In the vapour phase $BeCl_2$ tends to form a Chloro-bridged dimer which dissociates into the Linear monomer at high temperatures of the Order of 1200 K. The tendency to form halide Hydrates gradually decreases down the group. The dehydration Of hydrated chlorides, bromides and iodides Of Ca, Sr and Ba can be achieved on heating; However, the corresponding hydrated halides Of Be and Mg on heating suffer hydrolysis. The Fluorides are relatively less soluble than the Chlorides owing to their high lattice energies.
Salts of Oxoacids: The alkaline earth Metals also form salts of oxoacids. Some of These are :
Carbonates: Carbonates of alkaline earth Metals are insoluble in water and can be Precipitated by addition of a sodium or Ammonium carbonate solution to a solution Of a soluble salt of these metals. The solubility Of carbonates in water decreases as the atomic Number of the metal ion increases. All the Carbonates decompose on heating to give Carbon dioxide and the oxide. Beryllium Carbonate is unstable and can be kept only in The atmosphere of $CO_2$. The thermal stability Increases with increasing cationic size.
Sulphates: The sulphates of the alkaline earth Metals are all white solids and stable to heat. $BeSO_4,$ and $MgSO_4$ are readily soluble in water; The solubility decreases from $CaSO_4$ to $ BaSO_4$. The greater hydration enthalpies of $Be_2+$ and $Mg_2+$ ions overcome the lattice enthalpy factor And therefore their sulphates are soluble in Water.​​​​​​​
Nitrates: The nitrates are made by dissolution Of the carbonates in dilute nitric acid. Magnesium nitrate crystallises with six Molecules of water, whereas barium nitrate Crystallises as the anhydrous salt. This again Shows a decreasing tendency to form hydrates With increasing size and decreasing hydration Enthalpy. All of them decompose on heating to Give the oxide like lithium nitrate.
$2\text{M}(\text{NO}_3)_2\rightarrow2\text{MO}+4\text{NO}_2+\text{O}_2$
(M = Be. Mg. Ca. Sr. Ba)
Beryllium, the first member of the Group 2 Metals, shows anomalous behaviour as Compared to magnesium and rest of the Members. Further, it shows diagonal Relationship to aluminium which is discussed Subsequently.
i) Beryllium has exceptionally small atomic And ionic sizes and thus does not compare Well with other members of the group. Because of high ionisation enthalpy and Small size it forms compounds which are Largely covalent and get easily hydrolysed.
ii) Beryllium does not exhibit coordination Number more than four as in its valence Shell there are only four orbitals. The Remaining members of the group can have A coordination number of six by making Use of d-orbitals.
iii) The oxide and hydroxide of beryllium, Unlike the hydroxides of other elements in The group, are amphoteric in nature.
Diagonal Relationship between Beryllium and Aluminium-The ionic radius of 4 is estimated to be 31 pm; the charge/radius ratio is nearly the Same as that of the $Al^{3+}$ ion. Hence beryllium Resembles aluminium in some ways. Some of The similarities are:
i) Like aluminium, beryllium is not readily Attacked by acids because of the presence Of an oxide film on the surface of the metal.
ii) Beryllium hydroxide dissolves in excess of Alkali to give a beryllate ion, $[Be(OH)_4]^{2–}$ just As aluminium hydroxide gives aluminate Ion, $[Al(OH)_4]^–.$
iii) The chlorides of both beryllium and Aluminium have $Cl^–$ Bridged chloride Structure in vapour phase. Both the Chlorides are soluble in organic solvents And are strong Lewis acids. They are used As Friedel Craft catalysts.
iv) Beryllium and aluminium ions have strong Tendency to form complexes, $BeF_4^{2–}, AlF_6^{3–}.$​​​​​​​
  1. The dipositive oxidation state $(M2^+)$ is the Predominant valence of … elements.
  1. Group 2
  2. Group 1
  3. Group 17
  4. Group 18
  1. … the first member of the Group 2 metals.
  1. Magnesium
  2. Beryllium
  3. Barium
  4. Radium
  1. Except for beryllium halides, all other halides of alkaline earth metals are ionic in nature.
  1. Magnesium halides
  2. beryllium halides
  3. Calcium halides
  4. Radium halides
  1. The ionic radius of $Be^{2+}$ is estimated to be … pm.
  1. 310
  2. 500
  3. 50
  4. 31
  1. Beryllium carbonate can be kept only in the atmosphere of …
  1. $N_2$
  2. $H_2$
  3. $CO_2$
  4. $O_2$

Answer

  1. (a) Group 2
  2. (b) Beryllium
  3. (c) beryllium halides
  4. (d) 31
  5. (c) $ CO_2$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Read the passage given below and answer the following questions from 1 to 5.
A reagent that brings an electron pair to the reactive site is called a nucleophile (Nu:) i.e., nucleus seeking and the reaction is then called nucleophilic. A reagent that takes away an electron pair from reactive site is called electrophile (E+) i.e., electron seeking and the reaction is called electrophilic.
Electron Displacement Effects in Covalent Bonds The electron displacement in an organic molecule may take place either in the ground state under the influence of an atom or a substituent group or in the presence of an appropriate attacking reagent. The electron displacements due to the influence of an atom or a substituent group present in the molecule cause permanent polarlisation of the bond. Inductive effect and resonance effects are examples of this type of electron displacements. Temporary electron displacement effects are seen in a molecule when a reagent approaches to attack it. This type of electron displacement is called electrometric effect or polarisability effect.
Inductive Effect When a covalent bond is formed between atoms of different electronegativity, the electron density is more towards the more electronegative atom of the bond. Such a shift of electron density results in a polar covalent bond. Bond polarity leads to various electronic effects in organic compounds. Let us consider cholorethane $(CH_3CH_2Cl)$ in which the C–Cl bond is a polar covalent bond. It is polarised in such a way that the carbon-1 gains some positive charge $(\delta+)$ and the chlorine some negative charge $(\delta-)$ The fractional electronic charges on the two atoms in a polar covalent bond are denoted by symbol (delta) and the shift of electron density is shown by an arrow that points from$(\delta+)$ to $(\delta-)$ end of the polar bond.

In turn carbon-1, which has developed partial positive charge $(\delta+)$draws some electron density towards it from the adjacent C-C bond. Consequently, some positive charge$(\delta\delta+)$develops on carbon-2 also, where $(\delta\delta+)$ symbolises relatively smaller positive charge as compared to that on carbon – 1. In other words, the polar C – Cl bond induces polarity in the adjacent bonds. Such polarisation of σ- bond caused by the polarisation of adjacent $σ-$bond is referred to as the inductive effect.
Resonance Structure There are many organic molecules whose behaviour cannot be explained by a single Lewis structure. An example is that of benzene. Its cyclic structure containing alternating C–C single and C=C double bonds shown is inadequate for explaining its characteristic properties.

As per the above representation, benzene should exhibit two different bond lengths, due to C–C single and C=C double bonds. However, as determined experimentally benzene has a uniform C–C bond distances of 139 pm, a value intermediate between the C–C single(154 pm) and C=C double (134 pm) bonds. Thus, the structure of benzene cannot be represented adequately by the above structure. Further, benzene can be represented equally well by the energetically identical structures I and II.

Therefore, according to the resonance theory the actual structure of benzene cannot be adequately represented by any of these structures, rather it is a hybrid of the two structures (I and II) called resonance structures. The resonance structures (canonical structures or contributing structures) are hypothetical and individually do not represent any real molecule. They contribute to the actual structure in proportion to their stability.
Resonance Effect The resonance effect is defined as ‘the polarity produced in the molecule by the interaction of two π-bonds or between a π-bond and lone pair of electrons present on an adjacent atom’. The effect is transmitted through the chain. There are two types of resonance or mesomeric effect designated as R or M effect. (i) Positive Resonance Effect (+R effect) In this effect, the transfer of electrons is away from an atom or substituent group attached to the conjugated system. This electron displacement makes certain positions in the molecule of high electron densities. This effect in aniline is shown as : (ii) Negative Resonance Effect (- R effect) This effect is observed when the transfer of Electrons is towards the atom or substituent Group attached to the conjugated system. For Example in nitrobenzene this electron Displacement can be depicted as : The atoms or substituent groups, which represent +R or –R electron displacement effects are as follows: +R effect: – halogen, –OH, –OR, –OCOR, –NH2, –NHR, –NR2, –NHCOR, – R effect: $– COOH, –CHO, > C = O, – CN, – NO_2$ The presence of alternate single and double bonds in an open chain or cyclic system is termed as a conjugated system. These systems often show abnormal behaviour. The examples are 1,3- butadiene, aniline and nitrobenzene etc. In such systems, the π-electrons are delocalised and the system develops polarity.
Electromeric Effect (E effect) It is a temporary effect. The organic compounds having a multiple bond (a double or triple bond) show this effect in the presence of an attacking reagent only. It is defined as the complete transfer of a shared pair of π-electrons to one of the atoms joined by a multiple bond on the demand of an attacking reagent. The effect is annulled as soon as the attacking reagent is removed from the domain of the reaction. It is represented by E and the shifting of the electrons is shown by a curved arrow ( ). There are two distinct types of electromeric effect.
a) Positive Electrometric Effect (+E effect)- In this effect the π−electrons of the multiple bond are transferred to that atom to which the reagent gets attached. For example

b) Negative Electromeric Effect (–E effect) -In this effect the $\pi-$ electrons of the multiple bond are transferred to that atom to which the attacking reagent does not get attached. For example: When inductive and electromeric effects operate in opposite directions, the electomeric effect predominates.
  1. A reagent that brings an electron pair to the reactive site is called a …
  1. nucleophile
  2. electrophile
  3. amphoteric
  4. amphophillic
  1. A reagent that takes away an electron pair from reactive site is called ..
  1. nucleophile
  2. electrophile
  3. amphoteric
  4. amphophillic
  1. The … effect is defined as the polarity produced in the molecule by the interaction of two π-bonds or between a π-bond and lone pair of electrons present on an adjacent atom.
  1. hindrance
  2. inductive
  3. resonance
  4. hyperconjunction
  1. –OH group, represent … electron displacement effect.
  1. M+
  2. M-
  3. R-
  4. R+
  1. – COOH group, represent … electron displacement effect.
  1. M+
  2. M-
  3. R-
  4. R+
When anions and cations approach each other, the valence shell of anions are pulled towards the cation nucleus and thus, the shape of the anion is deformed. The phenomenon of deformation of anion by a cation is known as polarization and the ability of the cation to polarize the anion is called as polarizing power of cation. Due to polarization, sharing of electrons occurs between two ions to some extent and the bond shows some covalent character.
The magnitude of polarization depends upon a number of factors.

1. Out of $AlCl _3$ and $AlI _3$ which halides show maximum polarization?
2. Out of $AlCl _3$ and $CaCl _2$ which one is more covalent in nature?
3. The non-aqueous solvent like ether is added to the mixture of $LiCl , NaCl$ and KCl . Which will be extracted into the ether?
OR
Out of $CaF _2$ and $CaI _2$ which one has a minimum melting point?
Read the passage given below and answer the following questions from (i) to (v).
The identity of a substance is defined not only by the types of atoms or ions it contains, but by the quantity of each type of atom or ion. The experimental approach required the introduction of a new unit for amount of substances, the mole, which remains indispensable in modern chemical science. The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter. A mole is defined as the amount of substance containing the same number of discrete entities (atoms, molecules, ions, etc.) as the number of atoms in a sample of pure 12 C weighing exactly 12 g . One Latin connotation for the word "mole" is "large mass" or "bulk," which is consistent with its use as the name for this unit. The mole provides a link between an easily measured macroscopic property, bulk mass, and an extremely important fundamental property, number of atoms, molecules and so forth. The number of entities composing a mole has been experimentally determined to be $6.02214179 \times 10^{23}$. $6.02214179 \times 10^{23}$, a fundamental constant named Avogadro's number (NA) or the Avogadro constant in honor of Italian scientist Amedeo Avogadro. This constant is properly reported with an explicit unit of "per mole," a conveniently rounded version being $6.022 \times 10^{23} / mol$. Consistent with its definition as an amount unit, 1 mole of any element contains the same number of atoms as 1 mole of any other element. The masses of 1 mole of different elements, however, are different, since the masses of the individual atoms are drastically different. The molar mass of an element (or compound) is the mass in grams of 1 mole of that substance, a property expressed in units of grams per mole ( $g / mol$ ). The following questions are multiple choice questions. Choose the most appropriate answer:
i. A sample of copper sulphate pentahydrate contains 8.64 g of oxygen. How many grams of Cu is present in the sample?
  1. A sample of copper sulphate pentahydrate contains 8.64g of oxygen. How many grams of Cu is present in the sample?
  1. 0.952g
  2. 3.816g
  3. 3.782g
  4. 8.64g
  1. A gas mixture contains 50% helium and $50\%$ methane by volume. What is the percent by \ weight of methane in the mixture?
  1. $19.97\%$
  2. $20.05\%$
  3. $50\%$
  4. $80.03\%$
  1. The mass of oxygen gas which occupies 5.6 litres at STP could be:
  1. Gram atomic mass of oxygen
  2. One fourth of the gram atomic mass of oxygen
  3. Double the gram atomic mass of oxygen
  4. Half of the gram atomic mass of oxygen
  1. What is the mass of one molecule of yellow phosphorus? (Atomic mass of phosphorus = 30)
  1. $1.993 \times 10^{-22}$ mg
  2. $1.993 \times 10^{-19}$ mg
  3. $4.983 \times 10^{-20}$ mg
  4. $4.983 \times 10^{-23}$ mg
  1. The number of moles of oxygen in 1L of air containing $21\%$ oxygen by volume, in standard conditions is:
  1. $0.186$ mol
  2. $0.21$ mol
  3. $2.10$ mol
  4. $0.0093$ mol
Read the passage given below and answer the following questions from $1$ to $5$. Lithium metal is used to make useful alloys, for example with lead to make ‘white metal’ Bearings for motor engines, with aluminium to make aircraft parts, and with magnesium to make armour plates. It is used in Thermonuclear reactions. Lithium is also used to make electrochemical cells. Sodium is used To make a Na/Pb alloy needed to make $PbEt_4$​​​​​​​ and $PbMe_4​​​​​​​$​​​​​​​. These organolead compounds were Earlier used as anti-knock additives to petrol, But nowadays vehicles use lead-free petrol. Liquid sodium metal is used as a coolant in Fast breeder nuclear reactors. Potassium has a vital role in biological systems. Potassium Chloride is used as a fertilizer. Potassium Hydroxide is used in the manufacture of soft Soap. It is also used as an excellent absorbent of carbon dioxide. Caesium is used in devising Photoelectric cells. Points of Difference between Lithium and other Alkali Metals –
i) Lithium is much harder. Its m.p. and b.p. are higher than the other alkali metals.
ii) Lithium is least reactive but the strongest Reducing agent among all the alkali metals. On combustion in air it forms mainly Monoxide, $Li_2O$ and the nitride, $Li_3N$ unlike Other alkali metals.
 iii) LiCl is deliquescent and crystallises as a Hydrate, LiCl.$2H_2O$ whereas other alkali Metal chlorides do not form hydrates.
iv) Lithium hydrogencarbonate is not Obtained in the solid form while all other Elements form solid hydrogencarbonate.
v) Lithium unlike other alkali metals forms No ethynide on reaction with ethyne.
vi) Lithium nitrate when heated gives lithium Oxide, $Li_2O$, whereas other alkali metal Nitrates decompose to give the Corresponding nitrite. $4\text{LiNO}_3\rightarrow2\text{L}\text{i}_2\text{O}+4\text{NO}_2+\text{O}_2$ $2\text{NaNO}_3\rightarrow2\text{NaNO}_2+\text{O}_2$ vii) LiF and $Li_2O$ are comparatively much less Soluble in water than the corresponding Compounds of other alkali metals. Sodium carbonate is generally prepared by Solvay Process. In this process, advantage is Taken of the low solubility of sodium Hydrogencarbonate whereby it gets Precipitated in the reaction of sodium chloride with ammonium hydrogencarbonate. The Latter is prepared by passing $CO_2​​​​​​​$​​​​​​​ to a Concentrated solution of sodium chloride Saturated with ammonia, where ammonium Carbonate followed by ammonium Hydrogencarbonate are formed. The equations For the complete process may be written as $2\text{NH}_3+\text{H}_2\text{O}+\text{CO}_2\rightarrow{\text{(NH}_4)_2}\text{CO}_3$ $(\text{NH}_4)_2\text{CO}_3+\text{H}_2\text{O}+\text{CO}_2\rightarrow2\text{NH}_4\text{HCO}_3$ $\text{NH}_4\text{HCO}_3+\text{NaCl}\rightarrow\text{NH}_4\text{Cl}+\text{NaHCO}_3$ Sodium hydrogencarbonate crystal Separates. these are heated to give sodium Carbonate. The most abundant source of sodium chloride is sea water which contains $2.7$ to $2.9 \%$ by Mass of the salt. In tropical countries like India, Common salt is generally obtained by Evaporation of sea water. Approximately $50$ Lakh tons of salt are produced annually in India by solar evaporation. Crude sodium Chloride, generally obtained by crystallisation Of brine solution, contains sodium sulphate, Calcium sulphate, calcium chloride and Magnesium chloride as impurities. Calcium Chloride, $CaCl_2$​​​​​​​, and magnesium chloride, $MgCl_2$​​​​​​​ are impurities because they are Deliquescent (absorb moisture easily from the Atmosphere). To obtain pure sodium chloride, The crude salt is dissolved in minimum amount Of water and filtered to remove insoluble Impurities. The solution is then saturated with Hydrogen chloride gas. Crystals of pure Sodium chloride separate out. Calcium and Magnesium chloride, being more soluble than Sodium chloride, remain in solution. Sodium Hydroxide (Caustic Soda), NaOH is generally prepared Commercially by the electrolysis of sodium Chloride in Castner-Kellner cell. A brine Solution is electrolysed using a mercury Cathode and a carbon anode. Sodium metal Discharged at the cathode combines with Mercury to form sodium amalgam. Chlorine Gas is evolved at the anode. Cathod: $\text{Na}^++\bar{\text{e}}\xrightarrow{\text{Hg}}\text{Na}-\text{amalgam}$ Anode: $\text{Cl}^-\rightarrow\frac{1}{2}\text{Cl}_2+\text{e}^-$ The amalgam is treated with water to give Sodium hydroxxide and hydrogen gas. $2$ Na - amalgam $+ 2H_2O \rightarrow 2NaOH + 2Hg + H_2$​​​​​​​
  1. NaOH Sodium hydroxide is generally prepared Commercially by the electrolysis of … in Castner-Kellner cell.
  1. $NaCl$
  2. $Na_2CO_3$
  3. $NaHCO_3$
  4. $NaNH_2$
  1. … is used in the manufacture of soft Soap.
  1. Sodium Hydroxide
  2. Potassium Hydroxide
  3. Aluminium hydroxide
  4. Beryllium hydroxide
  1. … is used in devising Photoelectric cells.
  1. Hydrogen
  2. Lithium
  3. Caesium
  4. Helium
  1. … compounds were Earlier used as anti-knock additives to petrol.
  1. Organomagnesium
  2. Organosilicon
  3. Organochloride
  4. Organolead
  1. The sodium amalgam is treated with water to gives ….
  1. $NaOH$
  2. $Na_2CO_3$
  3. $NaHCO_3$
  4. $NaNH_2$​​​​​​​
Read the passage given below and answer the following questions from 1 to 5.
The s-block elements of the Periodic Table are those in which the last electron enters the outermost s-orbital. as the s-orbital can accommodate only two electrons, two Groups (1 & 2) belong to the s-block of the Periodic Table. Group 1 of the Periodic Table consists of the elements: Lithium, sodium, potassium, rubidium, caesium and Francium. They are collectively known as the alkali metals. These are so called because they form hydroxides on Reaction with water which are strongly alkaline in nature. The elements of Group 2 include beryllium, magnesium, Calcium, strontium, barium and radium. These elements With the exception of beryllium are commonly known as The alkaline earth metals. These are so called because their Oxides and hydroxides are alkaline in nature and these Metal oxides are found in the earth’s crust. The general electronic configuration of s-block elements is [noble gas] ns1 for alkali metals and [noble gas] $ns^2$ for Alkaline earth metals.

All the alkali metals have one valence electron, ns1 outside the noble gas core. The loosely held s-electron in the outermost Valence shell of these elements makes them the Most electropositive metals. They readily lose Electron to give monovalent M+ Ions. The monovalent ions (M+) are smaller than the parent atom. Hence they Are never found in free state in nature.
The alkali metal atoms have the largest sizes In a particular period of the periodic table. With increase in atomic number, the atom becomes Larger. the atomic and ionic Radii of alkali metals increase on moving down the group i.e., they increase in size while going From Li to Cs.
The ionization enthalpies of the alkali metals Are considerably low and decrease down the Group from Li to Cs. this is because the effect of increasing size outweighs the increasing Nuclear charge, and the outermost electron is very well screened from the nuclear charge.
The hydration enthalpies of alkali metal ions Decrease with increase in ionic sizes. $Li^+ > Na^+ > K^+ > Rb^+ > Cs^+ > Li^+$ Has maximum degree of hydration and For this reason lithium salts are mostly Hydrated, e.g., $LiCl·2H_2O$.
All the alkali metals are silvery white, soft and Light metals. Because of the large size, these Elements have low density which increases down The group from Li to Cs. However, potassium is Lighter than sodium. The melting and boiling Points of the alkali metals are low indicating Weak metallic bonding due to the presence of Only a single valence electron in them. The alkali Metals and their salts impart characteristic Colour to an oxidizing flame. This is because the Heat from the flame excites the outermost orbital Electron to a higher energy level. When the excited Electron comes back to the ground state . Alkali metals can therefore, be detected by The respective flame tests and can be Determined by flame photometry or atomic Absorption spectroscopy. These elements when Irradiated with light, the light energy absorbed May be sufficient to make an atom lose electron. This property makes caesium and potassium Useful as electrodes in photoelectric cells.
The alkali metals are highly reactive due to Their large size and low ionization enthalpy. The Reactivity of these metals increases down the Group.
Reactivity towards air: The alkali metals Tarnish in dry air due to the formation of Their oxides which in turn react with Moisture to form hydroxides. They burn Vigorously in oxygen forming oxides. Lithium forms monoxide, sodium forms Peroxide, the other metals form Superoxide. The superoxide $O^{2–}$ Ion is Stable only in the presence of large cations Such as K, Rb, Cs.
Reactivity towards water: The alkali Metals react with water to form hydroxide And dihydrogen.
$2\text{M}+2\text{H}_2\text{O}\rightarrow2\text{M}^++2\text{OH}^-+\text{H}_2$
(M = analkali metal)
Reactivity towards dihydrogen: The Alkali metals react with dihydrogen at About 673K (lithium at 1073K) to form Hydrides. All the alkali metal hydrides are Ionic solids with high melting points.
Reactivity towards halogens: The alkali Metals readily react vigorously with Halogens to form ionic halides, $M^+X^–$ .
Reducing nature: The alkali metals are Strong reducing agents, lithium being the Most and sodium the least powerful.
Solutions in liquid ammonia: The alkali Metals dissolve in liquid ammonia giving Deep blue solutions which are conducting in nature.
  1. The general electronic configuration of s-block elements is … for alkali metals.
  1. [noble gas] $ns^1$
  2. [noble gas] $ns^2$
  3. [noble gas] $ns^1np^1$
  4. [noble gas] $ns^1np^2$
  1. The general electronic configuration of s-block elements is … for alkaline earth metals.
  1. noble gas] $ns^1$
  2. [noble gas] $ns^2$
  3. [noble gas] $ns^1np^1$
  4. [noble gas] $ns^1np^2$
  1. The atomic and ionic Radii of alkali metals … on moving down the group.
  1. constant
  2. decrease
  3. increase
  4. All the above
  1. The hydration enthalpies of alkali metal ions … with … in ionic sizes.
  1. increase, decrease
  2. increase, increase
  3. decrease, decrease
  4. decrease, increase
  1. Which of the following element is strong reducing agent?
  1. Lithium
  2. Sodium
  3. Fluorine
  4. Helium
Read the passage given below and answer the following questions from 1 to 5.
The unusual properties of water in the Condensed phase (liquid and solid states) are Due to the presence of extensive hydrogen Bonding between water molecules. This leads To high freezing point, high boiling point, high Heat of vaporisation and high heat of fusion in Comparison to $H_2S$ and $H_2Se$. In comparison To other liquids, water has a higher specific Heat, thermal conductivity, surface tension, Dipole moment and dielectric constant, etc. these properties allow water to play a key role In the biosphere. In the gas phase water is a bent molecule with a bond angle of $104.5^\circ$ , and O–H bond length Of 95.7 pm
It is a highly polar molecule. Its orbital overlap. In the liquid Phase water molecules are associated together By hydrogen bonds. The crystalline form of water is ice. At Atmospheric pressure ice crystallises in the Hexagonal form, but at very low temperatures It condenses to cubic form.
Density of ice is Less than that of water. Therefore, an ice cube Floats on water. In winter season ice formed On the surface of a lake provides thermal Insulation which ensures the survival of the Aquatic life. This fact is of great ecological Significance. Structure of Ice Ice has a highly ordered three dimensional Hydrogen bonded structure. Examination of ice crystals with X-rays shows that each oxygen atom is Surrounded tetrahedrally by four other oxygen Atoms at a distance of 276 pm.
Hydrogen bonding gives ice a rather open Type structure with wide holes. These holes can Hold some other molecules of appropriate size Interstitially.
Water reacts with a large number of Substances. Some of the important reactions Are given below.
Amphoteric Nature: It has the ability to act as an acid as well as a base i.e., it behaves As an amphoteric substance. In the Brönsted Sense it acts as an acid with $NH_3$ and a base with $H_2S.$
$\text{H}_2\text{O}(\text{l})+\text{NH}_3(\text{aq})\rightleftharpoons\text{OH}^-(\text{aq})+\text{NH}^+_4\text{aq}$
$\text{H}_2\text{O}(\text{l})+\text{H}_2\text{S}(\text{aq})\rightleftharpoons\text{H}_3\text{O}^+(\text{aq})+\text{HS}^-\text{(aq)}$
The auto protolysis (self-ionzation) of water takes palace as follow:
$\text{H}_2\text{O}(\text{l})+\text{H}_2\text{O}(\text{l})\rightleftharpoons\text{H}_3\text{O}^+(\text{aq})+\text{OH}^-(\text{aq})$
$\text{acid-1 base-2 (acid-2) base-1}$
$\text{(acid) (base) (conjugate acid) (conjugate base)}$
Redox Reactions Involving Water: Water Can be easily reduced to dihydrogen by highly Electropositive metals.
$2\text{H}_2\text{O}(\text{l})+2\text{Na}\text{(s)}\rightarrow2\text{NaOH}\text{(aq)}+\text{H}_2\text{g}$
Thus. it is a great source of dihydrogen.
water is oxidished to $O_2$ during photosynthesis.
$6\text{CO}_2\text{g}+12\text{H}_2\text{O}(\text{l})\rightarrow\text{C}_6\text{H}_{12}\text{O}_6(\text{aq})+6\text{H}_2\text{O}{\text{l}}+6\text{O}_2\text{(g)}$
With fluorine also it is oxidised to $O_2.$
$2\text{F}_2\text{g}+2\text{H}_2\text{O}(\text{l})\rightarrow4\text{H}^+(\text{aq})+4\text{F}^-(\text{aq})+\text{O}_2\text{(G)}$
Hydrolysis Reaction: Due to high Dielectric constant, it has a very strong Hydrating tendency. It dissolves many ionic Compounds. However, certain covalent and Some ionic compounds are hydrolysed in water.
$\text{P}_4\text{O}_{10}(\text{s})+6\text{H}_2\text{O}(\text{l})\rightarrow4\text{H}_3\text{PO}_4\text{(aq)}$
$\text{SiCl}_4{\text{l}}+2\text{H}_2\text{O}(\text{l})\rightarrow\text{SiO}_2\text{(s)}+4\text{HCl}\text{(aq)}$
Hydrates Formation: From aqueous Solutions many salts can be crystallised as Hydrated salts. Such an association of water Is of different types viz., Coordinated water e.g.,

Hard and Soft Water- Rain water is almost pure (may contain some Dissolved gases from the atmosphere). Being a Good solvent, when it flows on the surface of The earth, it dissolves many salts. Presence of Calcium and magnesium salts in the form of Hydrogencarbonate, chloride and sulphate in Water makes water ‘hard’. Hard water does Not give lather with soap. Water free from Soluble salts of calcium and magnesium is Called Soft water. It gives lather with soap Easily. Temporary hardness is due to the presence of Magnesium and calcium hydrogen- Carbonates. It can be removed by:
Boiling: During boiling, the soluble $Mg(HCO_3)_2$ is converted into insoluble $Mg(OH)_2$ And $Ca(HCO_3)_2$ is changed to insoluble $CaCO_3$. It is because of high solubility product of $Mg(OH)_2$ as compared to that of $MgCO_3$, that $Mg(OH)_2$ is precipitated. These precipitates can Be removed by filtration. Filtrate thus obtained
Will be soft water.
$\text{Mg}(\text{HCO}_3)_2\xrightarrow{\text{Heating}}\text{Mg}(\text{OH})_2\downarrow+2\text{CO}_2\uparrow$
$\text{Ca}(\text{HCO}_3)_2\xrightarrow{\text{Heating}}\text{CaCO}_3\downarrow+\text{H}_2\text{O}+\text{CO}_2\uparrow$
Clark’s method: In this method calculated Amount of lime is added to hard water. It Precipitates out calcium carbonate and Magnesium hydroxide which can be filtered off.
Permanent Hardness is due to the presence of soluble salts of Magnesium and calcium in the form of Chlorides and sulphates in water. Permanent Hardness is not removed by boiling.
$\text{Ca}(\text{Hco}_3)_2+\text{Ca}(\text{OH)}_2\rightarrow2\text{CaCO}_3\downarrow2\text{H}_2\text{O}$
$\text{Mg}(\text{HCO)}_3+2\text{Ca}\text{(Oh)}_2\rightarrow2\text{CaCO}_3\downarrow+\text{Mg}(\text{OH)}_2\downarrow2\text{H}_2\text{O}$
Permanent Hardness is due to the presence of soluble salts of Magnesium and calcium in the form of Chlorides and sulphates in water. Permanent Hardness is not removed by boiling.
  1. In the gas phase water is a bent molecule with a bond angle of:
  1. $104.5^\circ$
  2. $94.5^\circ$
  3. $110.5^\circ$
  4. $95.5^\circ$
  1. At Atmospheric pressure ice crystallises in the … form.
  1. Cubic
  2. Hexagonal
  3. Octagonal
  4. Pentagonal
  1. Water free from Soluble salts of calcium and magnesium is called …
  1. hard water
  2. dry water
  3. soft water
  4. None of above
  1. Water has…. Nature.
  1. acidic
  2. basic
  3. neutral
  4. amphoteric
  1. Water is…. Molecule.
  1. Polar
  2. Non- Polar
  3. Ionic
  4. All the above
Read the passage given below and answer the following questions from 1 to 5.
Alkenes are unsaturated hydrocarbons containing at least one double bond. What should be the general formula of alkenes? If there is one double bond between two carbon atoms in alkenes, they must possess two hydrogen atoms less than alkanes. Hence, general formula for alkenes is $C_nH_{2n}$. Alkenes are also known as olefins (oil forming) since the first member, ethylene or ethene $(C_2H_4)$ was found to form an oily liquid on reaction with chlorine.
Structure of Double Bond Carbon-carbon double bond in alkenes consists of one strong sigma $(\sigma)$ bond (bond enthalpy about $397\ kJ\ mol^{–1)}$ due to head-on overlapping of $sp^2$ hybridised orbitals and one weak pi $\pi$ bond (bond enthalpy about $284\ kJ\ mol^{–1})$ obtained by lateral or sideways overlapping of the two 2p orbitals of the two carbon atoms. The double bond is shorter in bond length (134 pm) than the C–C single bond (154 pm). You have already read that the pi $(\pi)$ bond is a weaker bond due to poor sideways overlapping between the two 2p orbitals. Thus, the presence of the pi $(\pi)$bond makes alkenes behave as sources of loosely held mobile electrons. Therefore, alkenes are easily attacked by reagents or compounds which are in search of electrons. Such reagents are called electrophilic reagents. The presence of weaker$(\pi)$-bond makes alkenes unstable molecules in comparison to alkanes and thus, alkenes can be changed into single bond compounds by combining with the electrophilic reagents. Strength of the double bond (bond enthalpy, $681\ kJ\ mol^{–1}$) is greater than that of a carbon-carbon single bond in ethane (bond enthalpy, $348\ kJ\ mol^{–1}$). Orbital diagrams of ethene molecule are shown in Figure.

Geometrical isomerism: Doubly bonded Carbon atoms have to satisfy the remaining two Valences by joining with two atoms or groups. If the two atoms or groups attached to each Carbon atom are different, they can be Represented by YX C = C XY like structure. YX C = C XY can be represented in space in the Following two ways:

In (a), the two identical atoms i.e., both the X or both the Y lie on the same side of the Double bond but in (b) the two X or two Y lie Across the double bond or on the opposite Sides of the double bond. This results in Different geometry of (a) and (b) i.e. disposition Of atoms or groups in space in the two Arrangements is different. Therefore, they are Stereoisomers. They would have the same Geometry if atoms or groups around C = C bond Can be rotated but rotation around C = C bond Is not free. It is restricted. For understanding This concept, take two pieces of strong Cardboards and join them with the help of two Nails. Hold one cardboard in your one hand And try to rotate the other. Can you really rotate The other cardboard ? The answer is no. The Rotation is restricted. This illustrates that the Restricted rotation of atoms or groups around The doubly bonded carbon atoms gives rise to Different geometries of such compounds. The Stereoisomers of this type are called Geometrical isomers. The isomer of the type (a), in which two identical atoms or groups lie On the same side of the double bond is called Cis isomer and the other isomer of the type (b), in which identical atoms or groups lie on The opposite sides of the double bond is called Trans isomer. Thus cis and trans isomers Have the same structure but have different Configuration (arrangement of atoms or groups In space). Due to different arrangement of Atoms or groups in space, these isomers differ In their properties like melting point, boiling Point, dipole moment, solubility etc. Geometrical or cis-trans isomers of but-2-ene Are represented below:

Cis form of alkene is found to be more polar Than the trans form. For example, dipole Moment of cis - but - 2-ene is 0.33 Debye, Whereas, dipole moment of the trans form Is almost zero or it can be said that trans - but - 2 -ene is non-polar. This can be understood by drawing geometries of the two forms as given below from which it is clear that in the trans - but - 2 -ene, the two methyl groups are in opposite directions, Therefore, dipole moments of $C - CH_3$ bonds cancel, thus making the trans form non-polar.

In the case of solids, it is observed that the trans isomer has higher melting point than the cis form. Geometrical or cis-trans isomerism is also shown by alkenes of the types XYC = CXZ and XYC = CZW
Preparation – From alkynes: Alkynes on partial reduction with calculated amount of dihydrogen in the presence of palladised charcoal partially deactivated with poisons like sulphur
compounds or quinoline give alkenes. Partially deactivated palladised charcoal is known as Lindlar’s catalyst. Alkenes thus obtained are having cis geometry. However, alkynes on reduction with sodium in liquid ammonia form trans alkenes.

From alkyl halides: Alkyl halides (R-X) on heating with alcoholic potash (potassium hydroxide dissolved in alcohol, say, ethanol) eliminate one molecule of halogen acid to form alkenes. This reaction is known as dehydrohalogenation i.e., removal of halogen acid. This is example of $\beta-$elimination reaction, since hydrogen atom is eliminated from the $\beta$ carbon atom (carbon atom next to the carbon to which halogen is attached).

Nature of halogen atom and the alkyl group determine rate of the reaction. It is observed that for halogens, the rate is: iodine > bromine > chlorine, while for alkyl groups it is: tert > secondary > primary.
Physical properties Alkenes as a class resemble alkanes in physical properties, except in types of isomerism and difference in polar nature. The first three members are gases, the next fourteen are liquids and the higher ones are solids. Ethene is a colourless gas with a faint sweet smell. All other alkenes are colourless and odourless, insoluble in water but fairly soluble in non- polar solvents like benzene, petroleum ether. They show a regular increase in boiling point with increase in size i.e., every $–CH_2$ group added increases boiling point by 20–30 K. Like alkanes, straight chain alkenes have higher boiling point than isomeric branched chain compounds.
  1. The first three members of alkenes are …?
  1. Gases
  2. Liquids
  3. Solids
  4. None of above
  1. General formula for alkenes is ….?
  1. $C_nH_{2n+1}$
  2. $C_nH_{2n}$
  3. $C_nH_{2n-1}$
  4. $C_nH_{2n+2}$
  1. The colour of ethene gas is …?
  1. Red
  2. White
  3. Pale Green
  4. None of above
  1. The bond length of carbon carbon double bond is … pm ?
  1. 154
  2. 143
  3. 134
  4. 120
  1. Alkenes are also knows as …?
  1. Olefines
  2. Paraffines
  3. Oleofines
  4. Paracetofines
The phenomenon of the existence of two or more compounds possessing the same molecular formula but different properties is known as isomerism. Such compounds are called isomers. Compounds having the same molecular formula but different structures (manners in which atoms are linked) are classified as structural isomers. Structural isomers are classified as chain isomer, position isomer, functional group isomer. Meristematic arises due to different alkyl chains on either side of the functional group in the molecule and stereoisomerism and can be classified as geometrical and optical isomerism. Hyperconjugation is a general stabilising interaction. It involves delocalisation of $\sigma$ electrons of the C-H bond of an alkyl group directly attached to an atom of an unsaturated system or to an atom with an unshared p orbital. This type of overlap stabilises the carbocation because electron density from the adjacent $\sigma$ bond helps in dispersing the positive charge.

1. Why Isopentane, pentane and Neopentane are chain isomers?
OR
Why hyperconjugation is a permanent effect?
2. The molecular formula $C _3 H _8 O$ represents which isomer?
3. What type of isomerism is shown by Methoxypropane and ethoxyethane?
Read the passage given below and answer the following questions from 1 to 5. Chemistry deals with varieties of matter and change of one kind of matter into the other. Transformation of matter from one kind into another occurs through the various types of reactions. One important category of such reactions is Redox Reactions. Originally, the term oxidation was used to describe the addition of oxygen to an element or a compound. Because of the presence of dioxygen in the atmosphere (~20%), many elements combine with it and this is the principal reason why they commonly occur on the earth in the form of their oxides. The following reactions represent oxidation processes: $2\text{Mg}(\text{s})\rightarrow2\text{MgO}\text{ (S)}$ $\text{S}(\text{s})+\text{O}_2(\text{g})\rightarrow\text{SO}_2\text{ g}$ the term “oxidation” is defined as the addition of oxygen/electronegative element to a substance or removal of hydrogen/ electropositive element from a substance. In the beginning, reduction was considered as removal of oxygen from a compound. However, the term reduction has been broadened these days to include removal of oxygen/electronegative element from a substance or addition of hydrogen/ electropositive element to a substance. According to the definition given above, the following are the examples of reduction processes: $2\text{HgO}\text{S}\xrightarrow{\triangle}2\text{ Hg}(1)+\text{O}_2(\text{g})$ $2\text{HgCl}_2(\text{aq})+\text{SnCl}_2(\text{aq})\rightarrow\text{Hg}_2\text{Cl}_2(\text{s})+\text{SnCl}_4(\text{aq})$ In reaction simultaneous oxidation of stannous chloride to stannic chloride is also occurring because of the addition of electronegative element chlorine to it. It was soon realised that oxidation and reduction always occur simultaneously (as will be apparent by re-examining all the equations given above), hence, the word “redox” was coined for this class of chemical reactions.The reactions:
$2\text{Na}(\text{s})+\text{Cl2}\text{g}\rightarrow2\text{NaCl}(\text{s})$ $4\text{Na}(\text{s})+\text{O}_2\text{g}\rightarrow2\text{Na}_2\text{o}(\text{s})$ $2\text{Na}(\text{s})+\text{S}\text{(s)}\rightarrow2\text{Na}_2\text{S}(\text{s})$ are redox reactions because in each of these reactions sodium is oxidised due to the addition of either oxygen or more electronegative element to sodium. Simultaneously, chlorine, oxygen and sulphur are reduced because to each of these, the electropositive element sodium has been added. From our knowledge of chemical bonding we also know that sodium chloride, sodium oxide and sodium sulphide are ionic compounds and perhaps better written as $\mathrm{Na}+\mathrm{Cl}-(\mathrm{s}),\left(\mathrm{Na}^{+}\right)_2 \mathrm{O}^2-(\mathrm{s})$, and $\left(\mathrm{Na}^{+}\right)_2 \mathrm{~S}^{2-}(\mathrm{s})$. Development of charges on the species produced suggests us to rewrite the reactions in the following manner: For convenience, each of the above processes can be considered as two separate steps, one involving the loss of electrons and the other the gain of electrons. As an illustration, we may further elaborate one of these, say, the formation of sodium chloride. $2\text{Na}(\text{s})\rightarrow2\text{Na}^+\text{g}+2\bar{\text{e}}$ $\text{Cl}_2\text{g}+2\bar{\text{e}}\rightarrow2\text{C}\bar{\text{I}}\text{ (g)}$ Each of the above steps is called a half reaction, which explicitly shows involvement of electrons. Sum of the half reactions gives the overall reaction $2\text{Na}(\text{s})+\text{Cl}_2\text{(g)}\rightarrow2\text{Na}^+\text{CI}(\text{s})\text{ or } 2\text{NaCI}(\text{s})$ Above Reactions suggest that half reactions that involve loss of electrons are called oxidation reactions. Similarly, the half reactions that involve gain of electrons are called reduction reactions. To summarise, we may mention that Oxidation: Loss of electron(s) by any species. Reduction: Gain of electron(s) by any species. Oxidising agent: Acceptor of electron(s). Reducing agent: Donor of electron(s).
  1. Addition of electronegative element to a substance is known as..
  1. Oxidation
  2. Reduction
  3. Redox reaction
  4. All the above
  1. Removal of electronegative element to a substance is known as ..
  1. Oxidation
  2. Reduction
  3. Redox reaction
  4. All the above
  1. Acceptor of electrons is …
  1. Reducing Agent
  2. Catalytic Agent
  3. Oxidising Agent
  4. None of above
  1. Donor of electrons is…
  1. Organic Agent
  2. Catalytic Agent
  3. Oxidising Agent
  4. Reducing Agent
  1. Oxidation and Reduction occurs simultaneously is known as …
  1. Exothermic reaction
  2. Endothermic reaction
  3. Redox reaction
  4. Neutralization reaction
Read the passage given below and answer the following questions from (i) to (v).
The first concreteexplanation for the phenomenon of the blackbody radiation was given byMax Planck in 1900.An ideal body, which emits and absorbs radiations of allfrequencies uniformly, is called a black bodyand the radiation emitted by such a body is called black body radiation. Max Planck arrived at a satisfactory relationshipbymaking an assumption that absorption andemmission of radiation arises from oscillatori.e., atoms in the wall of black body.He suggested that atoms andmolecules could emit or absorb energy onlyin discrete quantities and not in a continuousmanner. He gave the name quantum to thesmallest quantity of energy that can be emitted or absorbed in the form of electromagnetic radiation. The energy (E) of aquantum of radiation is proportionalto its frequency (ν) and is expressed byequation .
$E = hυ.$
The proportionality constant, ‘h’ is knownas Planck’s constant and has the value6.$626\times 10^{–34}$ Js.In 1887, H. Hertz performed a very interestingexperiment in which electrons (or electriccurrent) were ejected when certain metals (forexample potassium, rubidium, caesium etc.)were exposed to a beam of light. The phenomenon is calledPhotoelectric effect. The results observed inthis experiment were:
  1. The electrons are ejected from the metalsurface as soon as the beam of light strikesthe surface, i.e., there is no time lagbetween the striking of light beam and theejection of electrons from the metal surface.
  2. The number of electrons ejected is proportional to the intensity or brightness of light.
  3. For each metal, there is a characteristicminimum frequency,ν0(also known asthreshold frequency) below which photoelectric effect is not observed. At afrequency $ν >ν_0$, the ejected electrons comeout with certain kinetic energy. The kineticenergies of these electrons increase withthe increase of frequency of the light used.
The particle nature of light posed a dilemmafor scientists. Theonly way to resolve the dilemma was to acceptthe idea that light possesses both particle andwave-like properties, i.e., light has dualbehaviour. Depending on the experiment, wefind that light behaves either as a wave or as astream of particles. Whenever radiationinteracts with matter, it displays particle likeproperties in contrast to the wavelike properties (interference and diffraction), whichit exhibits when it propagates. This conceptwas totally alien to the way the scientiststhought about matter and radiation and it tookthem a long time to become convincedof itsvalidity.
The study of emission or absorption spectra is referred to as spectroscopy.The emission spectra of atoms inthe gas phase, on the other hand, do not showa continuous spread of wavelength from redto violet, rather they emit light only at specificwavelengths with dark spaces between them.Such spectra are called line spectra or atomicspectra.The Swedishspectroscopist, Johannes Rydberg, noted that
all series of lines in the hydrogen spectrumcould be described by the following expression:
$\bar{\text{v}}=109,677\big(\frac{1}{\text{n}^2_1}-\frac{1}{\text{n}^2_2}\big)\text{cm}^{-1}$
The value $109,677 cm^{–1}$​​​​​​​ is called theRydberg constant for hydrogen. The first fiveseries of lines that correspond to $n_1= 1, 2, 3,4, 5$ are known as Lyman, Balmer, Paschen,Bracket and Pfund series, respectively.Neils Bohr (1913) was the first to explainquantitatively the general features of thestructure of hydrogen atom and its spectrum.He used Planck’s concept of quantisation ofenergy. Though the theory is not the modernquantum mechanics, it can still be used to rationalize many points in the atomic structureand spectra. Bohr’s model for hydrogen atomis based on the following postulates:
  1. The electron in the hydrogen atom canmove around the nucleus in a circular pathof fixed radius and energy. These paths arecalled orbits, stationary states or allowedenergy states. These orbits are arrangedconcentrically around the nucleus.
  2. The energy of an electron in the orbit doesnot change with time. However, theelectron will move from a lower stationarystate to a higher stationary state whenrequired amount of energy is absorbedby the electron or energy is emitted when electron moves from higher stationarystate to lower stationary state. The energychange does not takeplace in a continuous manner.
  3. The frequency of radiation absorbed oremitted when transition occurs between two stationary states that differ in energyby $\triangle\text{E},$ is given by:
$\text{v}=\frac{\triangle\text{E}}{\text{h}}=\frac{\text{E}_2-\text{E}_1}{\text{h}}$

Where E1 and E2 are the energies of the lower and higher allowed energy statesrespectively. This expression is commonly known as Bohr’s frequency rule.
  1. The angular momentum of an electron isquantised. In a given stationary state itcan be expressed as in equation
$\text{m}_{\text{e}}\text{vr}=\text{n}.\frac{\text{h}}{2\pi}\text{n}=1,2,3.....$
  1. The first concrete explanation for the phenomenon of the black body radiation was given by ….in 1900.
  1. Max Planck
  2. De Broglie
  3. Albert Einstein,
  4. Niels Bohr
  1. Which of the following equation is Planck’s equation?
  1. $E= mc^2​​​​​​​$
  2. $E = hυ$
  3. $E= hc^2​​​​​​​$
  4. $E= vc^2.$
  1. What is nature of light?
  1. Wave
  2. Particle
  3. Wave and Particle
  4. None of above
  1. The value …. is called theRydberg constant for hydrogen.
  1. $109,674cm^{–1}​​​​​​​$
  2. $109,675cm^{–1}​​​​​​​$
  3. $109,676cm^{–1}​​​​​​​$
  4. $109,677cm^{–1}$​​​​​​​
  1. …was the first to explain quantitatively the general features of the structure of hydrogen atom and its spectrum.
  1. Max Planck
  2. De Broglie
  3. Albert Einstein,
  4. Niels Bohr