Question
Read the passage given below and answer the following questions:
In ideally ionic structures, the coordination numbers of the ions are determined by electrostatic considerations. Cations surround themselves with as many anions as possible, and vice versa. This maximizes the attractions between neighbouring ions of opposite charge and hence maximizes the lattice energy of the crystal. This requirement led to the formulation of the radius ratio rule for ionic structures, in which the ions and the structure adopted for a particular compound depend on the relative sizes of the ions. Thus, for the stable ionic crystalline structures, there is definite radius ratio limit for a cation to fit perfectly in the lattice of anions, called radius ratio rule. This depends upon the ratio of radii of two types of ions $\frac{\text{r}_+}{r}$This ratio for coordination numbers $3, 4, 6$ and $8$ are respectively $0.155 - 0.225, 0.225 - 0.414, 0.414 - 0.732$ and $0.732 - 1.000$. The coordination number of ionic solids also depends upon temperature and pressure. On applying high pressure, coordination number increases. On the other hand, on applying high temperature, it decreases.
The following questions are multiple choice questions. Choose the most appropriate answer:
  1. The ionic radii of $K^+,Rb^+$ and $Br-$ are $137, 148$ and $195$pm. The coordination number of cation in RbBr and KBr structures are respectively.
  1. $8, 6$
  2. $6, 4$
  3. $6, 8$
  4. $4, 6$
  1. For a coordination number $4,$ the maximum limiting radius ratio is.
  1. $0.414$
  2. $0.732$
  3. $0.225$
  4. $0.155$
  1. If the radius of $Na^+$ ion is 95 pm and that of $Cl^-$ ion is $181$  pm, the coordination number of $Na^+$ ion is.
  1. $6$
  2. $4$
  3. $8$
  4. $12$
  1. Which is not the correct statement for ionic solids, in which positive and negative ions are held by strong electrostatic attractive forces?
  1. The radius ratio $\frac{\text{r}_+}{r}$ increases as coordination number increases.
  2. As the difference in size of ions increases, coordination number increases.
  3. When coordination number is eight, $\frac{\text{r}_+}{r}$ ratio lies between $0.225$ to $0.414.$
  4. In ionic solid of the type AX (ZnS, wurtzite), the coordination number of $Zn^2$ and $S^2$- respectively are $4 $and $4.$
  1. If the pressure of CsCl is increased, then its coordination number will.
  1. Increase
  2. Remain the same
  3. Decrease
  4. None of these.

Answer

  1. (a) $8, 6$
Explanation:
$\frac{\text{r}(\text{Rb}^+)}{\text{r}(\text{Rb}^-)}=\frac{148}{195}=0.76$ (C.N. $8$ above $0. 732$)
$\frac{\text{r}(\text{k}^+)}{\text{r}(\text{br}^-)}=\frac{137}{195}=0.702$ (C.N. $6$ between $0.414 - 0.732$)
  1. (a) $0.414$
  2. (a)$ 6$
Explanation:
$\frac{\text{r_+}}{\text{r_}}=\frac{\text{r}(\text{Na}^+)}{\text{r}(\text{CI}^-)}=\frac{95}{181}=0.524$
The radius ratio lies between $0.414 - 0.732.$
Hence, $Na^+$ ions prefer to occupy octahedral holes having coordination number $6.$
  1. (c) When coordination number is eight, $\frac{\text{r}_+}{\text{r}_-}$ ratio lies between $0.225$ to $0.414.$
Explanation:
When coordination number is $8 \frac{\text{r}_+}{\text{r}}$ratio lies between $0.732 - 1$
  1. (a) Increase
Explanation:
If the pressure of CsCl is increased, then its coordination number will increase.
 

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  2. 2
  3. 3
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  2. Europium $(Z = 63)$
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  4. Gadolinium $(Z = 64)$
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  1. Assertion: Copper metal gets readily corroded in acidic aqueous solution such as $HCl$ and dil. $H_2SO_4.$
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  1. Assertion: Tailing of mercury occurs on passing ozone through it.
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  2. Phenol.
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The transition elements have incompletely filled d-subshells in their ground state or in any of their oxidation states. The transition elements occupy position in betweens- and p-blocks in groups $3-12$ of the Periodic table. Starting from fourth period, transition elements consists of four complete series : Sc to $Zn, Y$ to Cd and La, $Hf$ to $Hg$ and $Ac, Rf$ to $Cn$. In general, the electronic configuration of outer orbitals of these elements is $(n - 1)d^{1-10} n^{1-2}$. The electronic configurations of outer orbitals of $Zn, Cd, Hg$ and $Cn$ are represented by the general formula $(n - 1)d^{10}ns^2$. All the transition elements have typical metallic properties such as high tensile strength, ductility, malleability. Except mercury, which is liquid at room temperature, other transition elements have typical metallic structures. The transition metals and their compounds also exhibit catalytic property and paramagnetic behaviour. Transition metal also forms alloys. An alloy is a blend of metals prepared by mixing the components. Alloys may be homogeneous solid solutions in which the atoms of one metal are distributed randomly among the atoms of the other.
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  1. High enthalpy of atomisation.
  2. Variable oxidation states.
  3. Paramagnetic behaviour.
  4. Colour of hydrated ions.
  1. Transition elements form alloys easily because they have.
  1. Same atomic number.
  2. Same electronic configuration.
  3. Nearly same atomic size.
  4. Same oxidation states.
  1. The electronic configuration of tantalum $(Ta)$ is:
  1. $[Xe]4f^05d^16s^2$
  2. $[Xe]4f^{14}5d^26s^2$
  3. $[Xe]4f^{14}5d^36s^2$
  4. $[Xe]4f^{14}5d^46s^2$
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  1. $3d^54s^1$
  2. $3d^54s^2$
  3. $3d^24s^2$
  4. $3d^34s^2$
  1. The correct statement(s) among the following is/ are:
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  2. All d and f-block elements form coloured ions.
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  1. $(I)$ only
  2. $(I)$ and $(II)$ only
  3. $(II)$ and $(III)$ only
  4. $(I), (II)$ and $(III)$