Question
Represent a galvanic cell in electrode and ions containing Cu electrode dipped in molar solution of copper sulphate and silver electrode dipped in molar solution of silver nitrate.
$\Big[\text{Given E}^\circ_{\frac{\text{Cu}^{2+}}{\text{Cu(s)}}}=0.34\text{V, E}^\circ_{\frac{\text{Ag}^+}{\text{Ag(s)}}}=0.80\text{V}\Big]$

Answer

Since, the reduction potential of copper is less than that of Ag, so Cu electrode behaves as anode and Ag electrode as cathode,
Cu | Cu2+ (aq) || Ag+ (aq) | Ag.

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