$\therefore$ calculated enthaly of hydrogenation of benzene $=3 \times(-119)$
$=-357 \mathrm{kJ} / \mathrm{mol}$
Resonance energy of benzene $=\Delta \mathrm{H}_{\mathrm{Exp}}-\Delta \mathrm{H}_{\mathrm{cal}}$
${-150=-357-\Delta \mathrm{H_{cal}}}$
${\Delta \mathrm{H}_{\mathrm{cal}}=-207 \;\mathrm{kJ} / \mathrm{mol}}$
Enthalpy of hydrogenation of benzene $=-207\; \mathrm{kJ} / \mathrm{mol}$
${\Delta _r}{G^o}$ (in $kJ\,mol^{-1}$) $=120-\frac {3}{8}\,T$
તો $T$ તાપમાને પ્રક્રિયા મિશ્રણનો મુખ્ય ઘટક કયો?