(આપેલઃ પરમાણુક્માંક $Sc : 21, Ti : 22, V : 23, Cr : 24, Mn : 25, Fe : 26$)
because Second electron is removed from stable
configuration \(3 \mathrm{~d}^5\)
\(\mathrm{Cr}^{+}:[\mathrm{Ar}] 3 \mathrm{~d}^5 4 \mathrm{~s}^0\)
\(\therefore\) No of unpaired \(\mathrm{e}^{-}\)in \(\mathrm{Cr}^{+}\)is \(5, \mathrm{n}=5\)
\(\text { So, Magnetic moment } =\sqrt{\mathrm{n}(\mathrm{n}+2)} \text { B.M }\)
\(=\sqrt{5(5+2)}=5.92 \mathrm{BM} \approx 6\)