MCQ
$(\sec \theta+\tan \theta-1)(\sec \theta-\tan \theta+1)=........$
- A$2\sec^2 \theta$
- B$\frac{1}{2}(\sec^2 \theta+\tan^2 \theta)$
- C$2$
- ✓$2\tan \theta$
$(\sec \theta+\tan \theta-1)(\sec \theta-\tan \theta+1)$
$=[\sec \theta+(\tan \theta-1)][\sec \theta-(\tan \theta-1)]$
$=\sec^2 \theta-(\tan \theta -1)^2$
$=\sec^2 \theta-\tan^2 \theta+2\tan \theta-1$
$=2\tan \theta$
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