Show that ^ -1 (2x 1-x^2 )=2 ^ -1 x. - Vidyadip

Question

Show that $\sin^{-1}\Big(2\text{x}\sqrt{1-\text{x}^2}\Big)=2\sin^{-1}\text{x}.$

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Answer

We have

$\text{L.H.S}=\sin^{-1}\Big(2\text{x}\sqrt{1-\text{x}^2}\Big)$

Putting $\text{x}=\sin\text{a},$ we get

$=\sin^{-1}\Big(2\sin\text{a}\sqrt{1-\sin^2\text{a}}\Big)$

$=\sin^{-1}(2\sin\text{a}\cos\text{a})$

$=\sin^{-1}(\sin2\text{a})$

$=2\text{a}$

$=2\sin^{-1}\text{a}$ $(\because\ \text{x}=\sin\text{a})$

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