Question
Show the following quadratic equation by factorization method: $5x^2 + 6x + 2 = 0$

Answer

$5x^2 + 6x + 2 = 0$ We will apply discriminant rule, $\text{x}=\frac{-\text{b}\pm\sqrt{\text{D}}}{2\text{a}}\ ...(\text{A})$ Where $D = b^2 - 4ac = 36 - 40 = 4 - 8 = -4$
From (A) $\text{x}=-\frac{-(-6)\pm\sqrt{-4}}{2.5}$ $=\frac{6\pm2\text{i}}{10}$ $=\frac{3\pm\text{i}}{5}$ $\therefore\text{x}=\frac{3}{5}+\frac{\text{i}}{5},\frac{3}{5}-\frac{\text{i}}{5}$

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