Simplify and solve the following equation. 16(y+3)-3 y+4(y+5)=0 - Vidyadip

Question

Simplify and solve the following equation.
$16(y+3)-3 y+4(y+5)=0$

✓

Answer

We have, $16(y+3)-3 y+4(y+5)=0$
Let us open the brackets,
$ \text { LHS }=16 y+48-3 y+4 y+20 $
The equation is $16 y+48-3 y+4 y+20=0$
$\Rightarrow \quad 17 y+68=0$
$\Rightarrow \quad 17 y=-68 \quad[$transposing 68 to RHS$]$
$\Rightarrow \quad y=\frac{-68}{17} \quad$ [dividing both sides by 17]
$\therefore \quad y=-4$

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