Question
Simplify the expression:
$\left( {3 + \sqrt 3 } \right)\left( {2 + \sqrt 2 } \right)$

Answer

$\left( {3 + \sqrt 3 } \right)\left( {2 + \sqrt 2 } \right)$
We need to apply distributive law to find value of $\left( {3 + \sqrt 3 } \right)\left( {2 + \sqrt 2 } \right)$
$\left( {3 + \sqrt 3 } \right)\left( {2 + \sqrt 2 } \right) = 3\left( {2 + \sqrt 2 } \right) + \sqrt 3 \left( {2 + \sqrt 2 } \right)$
$ = 6 + 3\sqrt 2 + 2\sqrt 3 + \sqrt 6 $
Therefore, on simplifying$ \left( {3 + \sqrt 3 } \right)\left( {2 + \sqrt 2 } \right)$,we get $6 + 3\sqrt 2 + 2\sqrt 3 + \sqrt 6 $

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