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Number Systems — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsNumber Systems2 Marks
Question
Simplify the following: $3\sqrt{3}+2\sqrt{27}+\frac{7}{3}$
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Answer

$3\sqrt{3}+2\sqrt{27}+\frac{7}{3}$ $=3\sqrt{3}+2\sqrt{3\times3\times3}+\frac{7}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}}$ $=3\sqrt{3}+6\sqrt{3}+\frac{7\sqrt{3}}{3}$ $=(3+6+\frac{7}{3})\sqrt{3}$ $=\frac{34}{3}\sqrt{3}$

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