- A$\left[ { - \frac{\pi }{6},\frac{\pi }{6}} \right]$
- B$\left[ {0,\frac{\pi }{2}} \right)$
- C$\left[ { - \frac{\pi }{2},\frac{\pi }{2}} \right]$
- D$\left[ { \frac{\pi }{6},\frac{\pi }{2}} \right]$
$y=\sin ^{-1}(1)$ when $x \rightarrow \infty=\frac{\pi}{2}$
When $x=0 \Rightarrow y=\sin ^{-1}\left(\frac{1}{2}\right)=\frac{\pi}{6}$
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$P$ (computer turns out to be defective given that it is produced in plant $T_1$ )
$=10 P\left(\right.$ computer turns out to be defective given that it is produced in plant $\left.T_2\right)$,
where $P(E)$ denotes the probability of an event $E$. A computer produced in the factory is randomly selected and it does not turn out to be defective. Then the probability that it is produced in plant $T_2$ is
$\left[\frac{x}{\sqrt{x^{2}-y^{2}}}+e^{\frac{y}{x}}\right] x \frac{d y}{d x}=x+\left[\frac{x}{\sqrt{x^{2}-y^{2}}}+e^{\frac{y}{x}}\right] y$ નો ઉકેલ
વક્ર $y=y(x)$ એે બિંદુઓ $(1,0)$ અને $(2 \alpha, \alpha)$ માંથી પસાર થાય, તો $\alpha>0$ નુ............ મૂલ્ય છે