Question
$\sin\begin{Bmatrix}2\cos^{-1}\Big(\frac{-3}{5}\Big)\end{Bmatrix}$ is equal to:
- $\frac{6}{25}$
- $\frac{24}{25}$
- $\frac{4}{5}$
- $-\frac{24}{25}$
✓
Answer
- $-\frac{24}{25}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
For any three vectors $\vec{\text{a}},\vec{\text{b}},\vec{\text{c}}$ the expression $\big(\vec{\text{a}}-\vec{\text{b}}\big).\big\{\big(\vec{\text{b}}-\vec{\text{c}}\big)\times\big(\vec{\text{c}}-\vec{\text{a}}\big)\big\}$ equals:
→- $\big[\vec{\text{a}}\vec{\text{b}}\vec{\text{c}}\big]$
- $2\big[\vec{\text{a}}\vec{\text{b}}\vec{\text{c}}\big]$
- $\big[\vec{\text{a}}\vec{\text{b}}\vec{\text{c}]}^2$
- None of these
What are the order and degree, respectively, of the differential equation:
$\Big(\frac{\text{d}^3\text{y}}{\text{dx}^3}\Big)^2=\text{y}^4+\Big(\frac{\text{dy}}{\text{dx}}\Big)^5?$
→$\Big(\frac{\text{d}^3\text{y}}{\text{dx}^3}\Big)^2=\text{y}^4+\Big(\frac{\text{dy}}{\text{dx}}\Big)^5?$
- 4, 5
- 2, 3
- 3, 2
- 5, 4
Shown below is the curve defined by the equation $y=\log (x+1)$ for $x \geq 0$.
Which of these is the area of the shaded region?
→Which of these is the area of the shaded region?
The principal solution of $\sin ^{-1}\left(\sin \left(\frac{5 \pi}{3}\right)\right)$ is
→If $\text{A}=\frac{1}{3}\begin{bmatrix} 1 & 1 & 2 \\ 2 & 1 & -2 \\ \text{x} & 2 & \text{y} \end{bmatrix}$ is prthogonal, than x + y =
→- 3
- 0
- -3
- 1
Let R = {(a, a), (b, b), (c, c), (a, b)} be a relation on set A = a, b, c. Then, R is:
- Identify relation.
- Reflexive.
- Symmetric.
- Antisymmetric.
If $f(x)=\sqrt{1+\cos ^2\left(x^2\right)}$, then the value of $f^{\prime}\left(\frac{\sqrt{\pi}}{2}\right)$ is
→If $\tan^{-1}(\text{x}-1)+\tan^{-1}\text{x}+\tan^{-1}(\text{x}+1)=\tan^{-1}3\text{x},$ then the values of x are:
→- $\pm\frac{1}{2}$
- $0,\frac{1}{2}$
- $0,-\frac{1}{2}$
- $0,\pm\frac{1}{2}$
Choose the correct answer: Area lying between the curves $y^2 = 4x$ and $y = 2x$ is:
→If the determinant $\begin{vmatrix}\text{a}&\text{b}&2\text{a}\alpha+3\text{b}\\\text{b}&\text{c}&2\text{b}\alpha+3\text{c}\\2\text{a}\alpha+ 3\text{b}&2\text{b}\alpha+3\text{c}&0\end{vmatrix}=0,$ then:
→