Six charges $+ q ,- q ,+ q ,- q ,+ q$ and $- q$ are fixed at the corners of a hexagon of side $d$ as shown in the figure. The work done in bringing a charge $q _0$ to the centre of the hexagon from infinity is :$\left(\varepsilon_0-\right.$ permittivity of free space)
  • A$0$
  • B$\frac{- q ^2}{4 \pi \varepsilon_0 d }$
  • C$\frac{- q ^2}{4 \pi \varepsilon_0 d }\left(3-\frac{1}{\sqrt{2}}\right)$
  • D$\frac{-q^2}{4 \pi \varepsilon_0 d }\left(6-\frac{1}{\sqrt{2}}\right)$
NEET 2022, Medium
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