\(C=\frac{\varepsilon_{0} A}{d}\) \(...(i)\)
Also capacitance = potential difference\(/\)charge \(.....(ii)\)
When battery is disconnected and the distance between the plates of the capacitor is increased then capacitance increases and charge remains constant.
since capacitance \(=\) potential difference\(/\)charge
\(\therefore\) Potential difference increases.