\(U\,\, = \,\,\frac{1}{2}{\varepsilon _0}{E^2}\,\, = \,\,\frac{1}{2}{\varepsilon _0}{\left( {\frac{V}{d}} \right)^2} \)
\(= \,\,\frac{1}{2} \times 8.85 \times {10^{ - 12}}{\,C^2}/N{m^2} \times {\left( {\frac{{300\,volt}}{{2 \times {{10}^{ - 3}}\,m}}} \right)^2}\,\, = \,\,0.1\,\,\,J/{m^3}\)