(આપેલ છે: $\mathrm{E}_{\mathrm{Sn}^{2+} / \mathrm{Sn}}^{0}=-0.14 \mathrm{\;V}$ $\left.\mathrm{E}_{\mathrm{Pb}^{+2}/{\mathrm{Pb}}}^{0}=-0.13 \;\mathrm{V}, \frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.06\right)$
\(\mathrm{Sn}(\mathrm{s})+\mathrm{Pb}^{+2}(\mathrm{aq}) \rightarrow \mathrm{Sn}^{+2}(\mathrm{aq})+\mathrm{Pb}(\mathrm{s})\dots (1)\)
Apply Nernst equation:
\(\mathrm{E}_{\text {cell}}=\mathrm{E}_{\text {cel }}^{0}-\frac{0.06}{2} \log \frac{\left[\mathrm{Sn}^{+2}\right]}{\left[\mathrm{Pb}^{+2}\right]}\)
\(\mathrm{E}_{\mathrm{cell}}^{0}=-0.13+0.14=0.01 \mathrm{V}\)
At equilibrium : \(E_{\text {cell}}=0\)
Substituting in \(( 1)\)
\(0=0.01-\frac{0.06}{2} \log \frac{\left[\mathrm{Sn}^{+2}\right]}{\left[\mathrm{Pb}^{+2}\right]}\)
\(\Rightarrow \quad \frac{1}{3}=\log \frac{\left[\mathrm{Sn}^{+2}\right]}{\left[\mathrm{Pb}^{+2}\right]}\)
\(\Rightarrow\; \frac{\left[\mathrm{Sn}^{+2}\right]}{\left\lceil\mathrm{Pb}^{+2}\right\rceil}=2.15\)
$C{u^{2 + }}_{({C_1}aq)} + Zn(s) \Rightarrow Z{n^{2 + }}_{({C_2}aq)} + Cu(s)$ તાપમાને મુક્તઊર્જા ફેરફાર $\Delta G$ એ .... નું વિધેય છે.
$A$. $\mathrm{Fe}$ $B$. $\mathrm{Mn}$ $C$. $\mathrm{Ni}$ $D$. $\mathrm{Cr}$ $E$. $\mathrm{Cd}$
Choose the correct answer from the options given below: