a
\(\frac{\ell}{ A }=129\; m ^{-1}\)

\(KCl\) solution \(1\) :

\(74.5\; ppm , R _{1}=100\; \Omega\)

\(KCl\) solution \(2\) :

\(149\; ppm , R _{2}=50 \;\Omega\)

\(149\;ppm , R _{2}=50 \;\Omega\)

Here, \(\frac{ ppm _{1}}{ ppm _{2}}=\frac{ M _{1}}{ M _{2}}\left(=\frac{ W _{1} / M _{0}}{ V } \times \frac{ V }{ W _{2} / M _{0}}\right)\)

\(\frac{\wedge_{1}}{\wedge_{2}}=\frac{\kappa_{1} \times \frac{1000}{M_{1}}}{\kappa_{2} \times \frac{1000}{M_{2}}}\)

\(=\frac{\kappa_{1}}{\kappa_{2}} \times \frac{M_{2}}{M_{1}}\)

\(=\frac{50}{100} \times 2\)

\(=\frac{\wedge_{1}}{\wedge_{2}}=1,000 \times 10^{-3}\)