Question
Solve:
$ 16 a^2-b^4 $
$ 16 a^2-b^4 $
✓
Answer
$ 16 a^2-b^4 $
$ =\left(4 a^2\right)^2-\left(b^2\right)^2 $
$ =\left(4 a^2+b^2\right)\left(4 a^2-b^2\right) $
$ =\left(4 a^2+b^2\right)\left[(2 a)^2-b^2\right] $
$ =\left(4 a^2+b^2\right)(2 a+b)(2 a-b) $
$ =\left(4 a^2\right)^2-\left(b^2\right)^2 $
$ =\left(4 a^2+b^2\right)\left(4 a^2-b^2\right) $
$ =\left(4 a^2+b^2\right)\left[(2 a)^2-b^2\right] $
$ =\left(4 a^2+b^2\right)(2 a+b)(2 a-b) $
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