- A$\big[-2,0\big]$
- B$\big[2,4\big]$
- C$\big[-2,0\big]\cup\big[2,4\big]$
- D$\text{None of these}$
Solution:
Given, $ 1\leq|\text{x} – 1|\leq3$
$\Rightarrow-3\leq(\text{x} – 1)\leq-1 $ or $1\leq(\text{x}-1)\leq3$
i.e. the distance covered is between 1 unit to 3 unit.
$\Rightarrow-2\leq \text{x}\leq0$ or $2\leq\text{x}\leq4$
Hence, the solution set of the given inequality is.
$\text{x}\in\big[-2, 0\big]\cup\big[2, 4\big]$
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