Question
Solve the following equation by trial and error method:
z - 3 = 2z - 5
z - 3 = 2z - 5
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x
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L.H.S.
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R.H.S.
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1
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1 - 3 = -2
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2 × 1 - 5 = -3
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2
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2 - 3 = -1
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2 × 2 - 5 = -1
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