Question
Solve the following equations. Check your result in case.$3 + 2x = 1 - x$
✓
Answer
$3 + 2x = 1 – x$
$\Rightarrow 2x + x = 1 – 3$(By transposing)
$\Rightarrow 3x = -2$
$\Rightarrow\text{x}=\frac{-2}{3}$
Check: $\text{L.H.S.}=3+2\text{x}=3+2\Big(\frac{-2}{3}\Big)$
$=\frac{3}{1}-\frac{4}{3}=\frac{9-4}{3}=\frac{2}{3}$
$\text{R.H.S.}=1-\text{x}=1-\big(\frac{-2}{3}\Big)=1+\frac{2}{3}$
$=\frac{3+2}{3}=\frac{5}{3}$
$\therefore\text{L.H.S = R.H.S}$ Hence $\text{x}=\frac{-2}{3}$
$\Rightarrow 2x + x = 1 – 3$(By transposing)
$\Rightarrow 3x = -2$
$\Rightarrow\text{x}=\frac{-2}{3}$
Check: $\text{L.H.S.}=3+2\text{x}=3+2\Big(\frac{-2}{3}\Big)$
$=\frac{3}{1}-\frac{4}{3}=\frac{9-4}{3}=\frac{2}{3}$
$\text{R.H.S.}=1-\text{x}=1-\big(\frac{-2}{3}\Big)=1+\frac{2}{3}$
$=\frac{3+2}{3}=\frac{5}{3}$
$\therefore\text{L.H.S = R.H.S}$ Hence $\text{x}=\frac{-2}{3}$
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