Question
Solve the following linear inequations in R:
$\frac{\text{x}-1}{3}+4<\frac{\text{x}-5}{5}-2$

Answer

$\frac{\text{x}-1}{3}+4<\frac{\text{x}-5}{5}-2$
$\frac{\text{x}-1+12}{3}<\frac{\text{x}-5-10}{5}$
5 (x - 1 + 12) < 3 (x - 5 - 10)
5(x + 11) < 3 (x - 15)
5x + 55 < 3x - 45
5x - 3x < -45 -55
2x < -100
x < -50
$\therefore$ The solution set is $(-\infty,-50)$

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