Question
Solve the following quadratic equation:
$9x^2 - 9(a + b)x + (2a^2 + 5ab + 2b^2) = 0$
$9x^2 - 9(a + b)x + (2a^2 + 5ab + 2b^2) = 0$
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Five year hence, the age of Jacob will be three times that of his son. Five years ago, Jacob's age was seven times that of his son. What are their present ages? Solve by substitution method.