Solve the inequality x+x 2 +x 3 <11 for real x. - Vidyadip

Question

Solve the inequality $x+\frac{x}{2}+\frac{x}{3}<11$ for real x.

✓

Answer

Here $x + \frac{x}{2} + \frac{x}{3} < 11$
$ \Rightarrow \frac{{6x + 3x + 2x}}{6} < 11$
$ \Rightarrow \frac{{11x}}{6} < 11$
Multiplying both sides by 6, we have
11x < 66
Dividing both sides by 11, we have
x < 6
Thus the solution set is $\left( { - \infty ,6} \right)$

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