Question
$S.P. = Rs. 9,250$ and discount = $7\frac{1}{2}\%$
✓
Answer
Selling price $(SP) = Rs. 9250$ discount$\% = 7\frac{1}{2}$% =$\frac{15}{2}\%$
Let marked price be Rs. $x$
$\text{Selling price}=\text{Marked price}-\frac{\text{Discount}\%}{100}\times\text{Marked price}$
$9250=\text{x}-\frac{15}{2\times100}\times\text{x}$
$9250=\frac{185\text{x}}{200}$
$\text{x}=\frac{9250\times220}{185}$
$\text{x}=\frac{1550000}{185}=\text{Rs.} \ 10000$
Hence, the marked price $= Rs. 10000$
Let marked price be Rs. $x$
$\text{Selling price}=\text{Marked price}-\frac{\text{Discount}\%}{100}\times\text{Marked price}$
$9250=\text{x}-\frac{15}{2\times100}\times\text{x}$
$9250=\frac{185\text{x}}{200}$
$\text{x}=\frac{9250\times220}{185}$
$\text{x}=\frac{1550000}{185}=\text{Rs.} \ 10000$
Hence, the marked price $= Rs. 10000$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Solve:
$ a^2-8 a b+16 b^2-25 c^2 $
→$ a^2-8 a b+16 b^2-25 c^2 $
The following items are purchased from showroom: T-Shirt worth $Rs. 1200$. Jeans worth $Rs. 1000. 2$ Skirts worth Rs. $1350$ each.
→If $x$ varies inversely as $y$ and $x = 20$ when $y = 600$, find y when $x = 400.$
→Find the product: $\frac{6\text{x}}{5}\big(\text{x}^3+\text{y}^3)$
→The circumference of the base of a cylinder is $88\ cm$ and its height is $60\ cm$. Find the volume of the cylinder and its curved surface area.
→(i) Add $5 \text{x}^2-13 \text{x} \text{y}+4 \text{y}^2-9$ and $7 \text{y}^2+5 \text{x} \text{y}-12 \text{x}^2+13.$
(ii) Subtract $-3 \text{p}^2+3 \text{pq}+3 \text{p} \text{x}$ from $3 \text{p}(-\text{p}-\text{a}-\text{r}).$
→(ii) Subtract $-3 \text{p}^2+3 \text{pq}+3 \text{p} \text{x}$ from $3 \text{p}(-\text{p}-\text{a}-\text{r}).$
Solve Cryptarithms. $\ \ \ \ \ \ \ \ \ \ \ \text{A}\ \ \ \ \text{B}\\\ \ \ \ \ \underline{+\ \ \ 3\ \ \ \ \ 7\ }\\\ \ \ \ \ {\ \ \ \ \ \ 9\ \ \ \ \text{A}\ }$
→$ABCD$ is a parallelogram in which $\angle\text{A}=110^\circ.$ Find the measure of each of the angles $\angle\text{A},\angle\text{B}$ and $\angle\text{D.}$
→Find the values of $X$ and $Y$ in the following parallelogram.
→A truck covers a distance of $510\ km$ in $34$ litres of diesel. How much distance would it cover in $20$ litres of diesel$?$
→