Standard enthalpy of vapourisation for CCl_4 is 30.5 ~kJ ~mol^ -1… - Vidyadip

MCQ

Standard enthalpy of vapourisation for $\mathrm{CCl}_4$ is $30.5 \mathrm{~kJ} \mathrm{~mol}^{-1}$. Heat required for vapourisation of $284 \mathrm{~g}$ of $\mathrm{CCl}_4$ at constant temperature is_______ $\mathrm{kJ}$. (Given molar mass in $\mathrm{g} \mathrm{mol}^{-1} ; \mathrm{C}=12, \mathrm{Cl}=35.5$ )

A
$78$
B
$12$
C
$46$
✓
$56$

✓

Answer

Correct option: D.

$56$

d
$ \Delta \mathrm{H}_{\text {vap }}^0 \mathrm{CCl}_4=30.5 \mathrm{~kJ} / \mathrm{mol} $

$ \text { Mass of } \mathrm{CCl}_4=284 \mathrm{gm} $

$ \text { Molar mass of } \mathrm{CCl}_4=154 \mathrm{~g} / \mathrm{mol} $

$ \text { Moles of } \mathrm{CCl}_4=\frac{284}{154}=1.844 \mathrm{~mol} $

$ \Delta \mathrm{H}_{\text {vap }}{ }^{\circ} \text { for } 1 \mathrm{~mole}=30.5 \mathrm{~kJ} / \mathrm{mol} $

$ \Delta \mathrm{H}_{\text {vap }}{ }^{\circ} \text { for } 1.844 \mathrm{~mol}=30.5 \times 1.844 $

$ \quad=56.242 \mathrm{~kJ}$

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