MCQ
At $STP$, for complete combustion of $3\, g \,C_2H_6$ the required volume of $O_2$ will be - ............. $\mathrm{litre}$
- A$78.4$
- ✓$7.84$
- C$2.78$
- D$6.23$
✓
Answer
Correct option: B.
$7.84$
b
$\mathrm{C}_{2} \mathrm{H}_{6}+\frac{7}{2} \mathrm{O}_{2} \rightarrow 2 \mathrm{CO}_{2}+3 \mathrm{H}_{2} \mathrm{O}$
$\mathrm{C}_{2} \mathrm{H}_{6}+\frac{7}{2} \mathrm{O}_{2} \rightarrow 2 \mathrm{CO}_{2}+3 \mathrm{H}_{2} \mathrm{O}$
mol of $\mathrm{C}_{2} \mathrm{H}_{6}=\frac{3\, \mathrm{gm}}{30}=0.1$
$\operatorname{mol} {\text{ of }}{{\text{O}}_2} = \frac{7}{2} \times \left( {\operatorname{mol} \,{\text{of}}\,{{\text{C}}_2}{{\text{H}}_6}} \right)$
$ = 0.35$
${\text{vol}}{\text{. of }}{{\text{O}}_2}({\text{ at S}}.{\text{T}}{\text{.P}}) = 0.35 \times 22.4$
$ = 7.84\,lit$
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