Question
- State first law of thermodynamics.
- Heat (q) and work function (w) individually are not state functions but their sum is always a state function. Why?
- Define extensive property with example.
$\Delta\text{U}=\text{q}+\text{w}$
$\text{q}+\text{w}=\Delta\text{U}$
$\Delta\text{U}$ is internal energy change which is state function because it depends upon initial and final state of the system and not on path, therefore, 'q + w' is state function.
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$3\text{CH}\equiv\text{CH}(\text{g})\rightleftharpoons\text{C}_6\text{H}_6(\text{g})$ assuming ideal gas behaviour, $\Delta_\text{f}\text{G}^\circ[\text{HC}\equiv\text{CH(g)}]=2.09\times10^5\text{J mol}^{-1},$ $\Delta_\text{f}\text{G}^\circ[\text{C}_6\text{H}_6(\text{g})]=1.24\times10^5\text{J mol}^{-1},$ R = 8.314JK-1 mol-1.
