A wire can be broken by applying a load of $200\, N$. The force required to break another wire of the same length and same material, but double in diameter, is .......... $N$
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Breaking force $=$ Breaking stress $\times$ Area
$\frac{F_{1}}{F_{2}}=\left(\frac{r_{1}}{r_{2}}\right)^{2}$
$\frac{200}{\mathrm{F}_{2}}=\left(\frac{\mathrm{r}}{2 \mathrm{r}}\right)^{2} \Rightarrow \mathrm{F}_{2}=800 \mathrm{N}$
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