તેથી, \(\Delta U = q + W\)
\(W = -P_{ext} \Delta V = -P_{ext} (V_2 - V_1) = -P_{ext}(2.5 - 2) = -1 (0.5) = -0.5 \,lit. atm\)
નોંધ: \(1\, lit - atm = 101.3\, Joule, 1\, Calorie = 4.2\, Joule\)
તેથી,\(W = -0.5 × 101.3 = -50.65\) જુલ
\(\Delta U = q + W = 300 + (-50.65) = 249.35 \,J\)
| પ્રક્રમ | $\Delta H / kJ\,mol ^{-1}$ | $\Delta S / J K^{-1}$ |
| $A$ | $-25$ | $-80$ |
| $B$ | $-22$ | $40$ |
| $C$ | $25$ | $-50$ |
| $D$ | $22$ | $20$ |
$H_2O _{(g)} + C_{(s)} = CO_{(g)} + H_{2{(g)}}$; $\Delta H = 131\, KJ$, $CO_{(g)} + \frac{1}{2}\,O_{2{(g)}} = CO_2$$_{(g)}$ ; $\Delta H = -282\, KJ,H_2$ $_{(g)}$$+ \frac{1}{2}\,O_2$$_{(g)}$ $= H_2O$$_{(g)}$; $\Delta H = - 242\, KJ, $ $C_{(s)}$ $+ O_2$ $_{(g)}$ $= $ $ CO_2$ $_{(g)}$; $\Delta$ $H = - x\,\,KJ$