MCQ
Study the given figure and answer the question that follow:
Image
Write the equation representing the reaction that occurs.
  • A
    At the Cathode: $Cu -2 e ^{-} \rightarrow Cu ^{2+}$
    At the Anode: $Cu ^{2+}+2 e ^{-} \rightarrow Cu$
  • B
    At the Cathode: $Cu ^{+}+2 e ^{-} \rightarrow Cu$
    At the Anode: $Cu ^{2-}-2 e ^{-} \rightarrow Cu ^{2+}$
  • C
    Both (a) and (b)
  • D
    At the Cathode: $Cu ^{2+}+2 e ^{-} \rightarrow Cu$
    At the Anode: $Cu -2 e ^{-} \rightarrow Cu ^{2+}$

Answer

D. At the Cathode: $Cu ^{2+}+2 e ^{-} \rightarrow Cu$
At the Anode: $Cu -2 e ^{-} \rightarrow Cu ^{2+}$
Explanation: Electrode on the left side is the oxidising electrode because anode is always connected to positive terminal of the battery, where copper atoms lose electrons at this electrode.
Hence, The correct equation representing the reaction that occurs during the electrolysis of copper(II) sulphate is:
At the Cathode: $Cu ^{2+}+2 e ^{-} \rightarrow Cu$
At the Anode: $Cu \rightarrow Cu ^{2+}+2 e^{-}$

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