Question
Subtract $7 p(3 q+7 p)$ from $8 p(2 p-7 q)$.
✓
Answer
We have, $8 p(2 p-7 q)=16 p^2-56 p q$
and $7 p(3 q+7 p)=21 p q+49 p^2$
$\therefore$ On subtracting, we get
and $7 p(3 q+7 p)=21 p q+49 p^2$
$\therefore$ On subtracting, we get
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