MCQ
Sulphur molecule is converted into sulphur ion, when it
  • Gains two electrons
  • B
    Loses two electrons
  • C
    Gains two protons
  • D
    Shares two electrons

Answer

Correct option: A.
Gains two electrons
a
(a)$\frac{1}{8}{S_8} + 2{e^ - }\, \to \,{S^{2 - }}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Best method of preparing alkyl chloride is
Identify the correct option
(image) is prepared best by the reaction
Which of the following compound gives yellow solid product when reacts with $NaOI$ ?
What is electronic arrangement of metal atom/ion in octahedral complex with $d^4$ configuration, if ${\Delta _0} < $ pairing energy.
$A\xrightarrow{{}}{(C{H_3})_2}C = CHCOC{H_3}\,\,\,\,A$  is
The general formula ${(RCO)_2}O$ represents
$EDTA$  has coordination number
The set of correct statements is:

$(i)$ Manganese exhibits $+7$ oxidation state in its oxide.

$(ii)$ Ruthenium and Osmium exhibit $+8$ oxidation in their oxides.

$(iii)$ $Sc$ shows $+4$ oxidation state which is oxidizing in nature.

$(iv)$ $Cr$ shows oxidising nature in $+6$ oxidation state.

Answer the following by appropriately matching the lists based on the information given in the paragraph $List-I$ includess starting materials and reagents of selected chemical reactions. $List-II$ gives structures of compounds that may be formed as intermediate products and/or final products from the reactions of $List-I$

($1$) Which of the following options has correct combination considering $List-I$ and $List-II$?

$(1) (III), (S), (R)$ $(2) (IV), (Q), (R)$ $(3) (III), (T), (U)$ $(4) (IV), (Q), (U)$

($2$) Which of the following options has correct combination considering $List-I$ and $List-II$?

$(1) (I), (Q), (T), (U)$ $(2) (II), (P), (S), (U)$ $(3) (II), (P), (S), (T)$ $(4) (I), (S), (Q), (R)$

Give the answer quetion ($1$) and ($2$)