
$\mathrm{e}_{2}=\frac{\omega_{2}}{\theta_{1}}$ $...(2)$
$e_{\text {net }}=\frac{\omega_{1}+\omega_{2}}{\theta_{\text {req }}}$
substituting $e_{1}$ and $e_{2}$ from equation
$(1)$ and $( 2)$
$e_{\mathrm{net}}=\frac{\theta_{\mathrm{req}} \mathrm{e}_{1}+\theta_{\mathrm{req}} \mathrm{e}_{2}-\omega_{1} \mathrm{e}_{2}}{\theta_{\mathrm{req}}}$
$e_{n e t}=e_{1}+e_{2}-e_{1} e_{2}$

The correct relation between these parameters are
$(A)$ Internal energies at $\mathrm{A}$ and $\mathrm{B}$ are the same
$(B)$ Work done by the gas in process $\mathrm{AB}$ is $\mathrm{P}_0 \mathrm{~V}_0 \ln 4$
$(C)$ Pressure at $C$ is $\frac{P_0}{4}$
$(D)$ Temperature at $\mathrm{C}$ is $\frac{\mathrm{T}_0}{4}$