$f=\frac{\Delta \mathrm{U}}{(\Delta \mathrm{Q})_{\mathrm{P}}}=\frac{(\Delta \mathrm{Q})_{\mathrm{V}}}{(\Delta \mathrm{Q})_{\mathrm{P}}}=\frac{\mu \mathrm{C}_{\mathrm{V}} \Delta \mathrm{T}}{\mu \mathrm{C}_{\mathrm{P}} \Delta \mathrm{T}}=\frac{1}{\gamma}$
For diatomic gas $\gamma=\frac{7}{5} \Rightarrow f=\frac{5}{7}$
Statement $2 :$ The temperature of a gas remains constant in an adiabatic process.
Step $1$ It is first compressed adiabatically from volume $V_{1}$ to $1 \;m ^{3}$.
Step $2$ Then expanded isothermally to volume $10 \;m ^{3}$.
Step $3$ Then expanded adiabatically to volume $V _{3}$.
Step $4$ Then compressed isothermally to volume $V_{1}$. If the efficiency of the above cycle is $3 / 4$, then $V_{1}$ is ............ $m^3$

| Process | Condition |
| $(I)$ Adiabatic | $(A)\; \Delta W =0$ |
| $(II)$ Isothermal | $(B)\; \Delta Q=0$ |
| $(III)$ Isochoric | $(C)\; \Delta U \neq 0, \Delta W \neq 0 \Delta Q \neq 0$ |
| $(IV)$ Isobaric | $(D)\; \Delta U =0$ |
Step $1$ It is first compressed adiabatically from volume $V_{1}$ to $1 \;m ^{3}$.
Step $2$ Then expanded isothermally to volume $10 \;m ^{3}$.
Step $3$ Then expanded adiabatically to volume $V _{3}$.
Step $4$ Then compressed isothermally to volume $V_{1}$. If the efficiency of the above cycle is $3 / 4$, then $V_{1}$ is ............ $m^3$