Surface tension of a soap solution is 1.9 10^ - 2 N/m. Work done … - Vidyadip

MCQ

Surface tension of a soap solution is $1.9 \times {10^{ - 2}}N/m$. Work done in blowing a bubble of $2.0\, cm$ diameter will be

A
$7.6 \times {10^{ - 6}}\pi $ joule
✓
$15.2 \times {10^{ - 6}}\pi $ joule
C
$1.9 \times {10^{ - 6}}\pi $ joule
D
$1 \times {10^{ - 4}}$ joule

✓

Answer

Correct option: B.

$15.2 \times {10^{ - 6}}\pi $ joule

b
(b) $W = 8\pi {R^2}T = 8\pi \times {(1 \times {10^{ - 2}})^2} \times 1.9 \times {10^{ - 2}}$=$15.2 \times {10^{ - 6}}\pi\, J$

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