MCQ
${\tan ^{ - 1}}1 + {\tan ^{ - 1}}2 + {\tan ^{ - 1}}3 = $
- A$\frac{\pi }{2}$
- B$\frac{\pi }{4}$
- C$0$
- ✓એકપણ નહીં.
$ = {\tan ^{ - 1}}1 + \pi + {\tan ^{ - 1}}\left( {\frac{5}{{ - 5}}} \right)$
$ = {\tan ^{ - 1}}1 + \pi - {\tan ^{ - 1}}1 = \pi $.
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કારણ $(R) : \vec b $ એ $\vec c $ ને લંબ હોય , તો $\vec b \, \times \,\vec c \,\, = \,\,0$