MCQ
${\tan ^{ - 1}}\left[ {\frac{{\cos x}}{{1 + \sin x}}} \right] = $
- ✓$\frac{\pi }{4} - \frac{x}{2}$
- B$\frac{\pi }{4} + \frac{x}{2}$
- C$\frac{x}{2}$
- D$\frac{\pi }{4} - x$
$ = {\tan ^{ - 1}}\left[ {\frac{{2\,\sin \,(\pi /4 - x/2)\,\cos \,(\pi /4 - x/2)}}{{2\,{{\cos }^2}\,(\pi /4 - x/2)}}} \right]$
$ = {\tan ^{ - 1}}\tan \,\left( {\frac{\pi }{4} - \frac{x}{2}} \right) = \frac{\pi }{4} - \frac{x}{2}$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.