MCQ
$tan^{-1}\left(\frac{2a-b}{b\sqrt{3}}\right)+tan^{-1}\left(\frac{2b-a}{a\sqrt{3}}\right)=.....$
- A$\frac{\pi }{6}$
- B$\frac{\pi }{4}$
- ✓$\frac{\pi }{3}$
- D$\frac{\pi }{2}$
$tan^{-1}\left(\frac{2a-b}{b\sqrt{3}}\right)+tan^{-1}\left(\frac{2b-a}{a\sqrt{3}}\right)$
$=tan^{-1\left\{\frac{\frac{2a-b}{b\sqrt{3}}+\frac{2b-a}{a\sqrt{3}}}{1-(\frac{2a-b}{b\sqrt{3}})(\frac{2b-a}{a\sqrt{3}})}\right\}}$
(સાદું આપતા)
$=tan^{-1}(\sqrt3)$
$= \frac{\pi}{3}$
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$\begin{array}{|l|l|l|l|l|l|} \hline X=x & 0 & 1 & 2 & 3 & 4 \\ \hline P(X=x) & \frac{1}{3} & \frac{1}{2} & 0 & \frac{1}{6} & 0 \\ \hline \end{array}$
, then