MCQ
$\tan A + \cot (180^\circ + A) + \cot (90^\circ + A) + \cot (360^\circ - A)$
- ✓$0$
- B$2\tan A$
- C$2\cot A$
- D$2(\tan A - \cot A)$
✓
Answer
Correct option: A.
$0$
a
(a) $\tan A + \cot (180^\circ + A) + \cot (90^\circ + A) + \cot (360^\circ - A)$
(a) $\tan A + \cot (180^\circ + A) + \cot (90^\circ + A) + \cot (360^\circ - A)$
$ = \tan A + \cot A - \tan A - \cot A = 0$.
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